Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
v is image distance
Magnification,
So, the magnification of the lens is 3.
Which optical device can focus light to a point through reflection?
1 answer:
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Answer:
Difference in the angle of refraction = 0.3°
41.04° is the minimum angle of incidence.
Explanation:
Angle of incidence = 38.0°
For yellow light :
Using Snell's law as:
Where,
Θ₁ is the angle of incidence
Θ₂ is the angle of refraction
n₁ is the refractive index for yellow light which is 1.523
n₂ is the refractive index of air which is 1
So,
Angle of refraction for yellow light = sin⁻¹ 0.9377 = 69.67°.
For green light :
Using Snell's law as:
Where,
Θ₁ is the angle of incidence
Θ₂ is the angle of refraction
n₁ is the refractive index for green light which is 1.526
n₂ is the refractive index of air which is 1
So,
Angle of refraction for green light = sin⁻¹ 0.9395 = 69.97°.
The difference in the angle of refraction = 69.97° - 69.67° = 0.3°
Calculation of the critical angle for the yellow light for the total internal reflection to occur :
The formula for the critical angle is:
Where,
is the critical angle
is the refractive index of the refractive medium.
is the refractive index of the incident medium.
n₁ is the refractive index for yellow light which is 1.523 (incident medium)
n₂ is the refractive index of air which is 1 (refractive medium)
Applying in the formula as:
The critical angle is = sin⁻¹ 0.6566 = 41.04°