Physical properties of a bag of microwaveable popcorn are the mass of it, the color of it, the size of it, and the weight of it. Two chemical properties of a bag of microwavable popcorn are it changed from seeds to popcorn and it popped.
The element used in advertising signs is neon.
Answer:
The solubility of MnS will decrease on addition of KOH solution.
Explanation:
As per the equation given:
On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.
Now when the we are adding aqueous KOH solution, it will dissociate as:
Thus it will further furnish more hydroxide ion,
This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.
Thus the solubility of MnS will decrease on addition of KOH solution.
Barfoed's test is a concoction test utilized for identifying the nearness of monosaccharides. It depends on the diminishment of copper(II) acetic acid derivation to copper(I) oxide (Cu2O), which frames a block red hasten.
Barfoed's reagent comprises of a 0.33 molar arrangement of unbiased copper acetic acid derivation in 1% acidic corrosive arrangement. The reagent does not keep well and it is, thusly, fitting to make it up when it is really required. May store uncertainly as per a few MSDS's.
Answer:
C 8.09 SO2 gas
Explanation:
As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:
PV = nRT
PV / RT = n
1atm*3L / 0.082atmL/molK*298K =¨
0.123 moles of gas you have.
Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).
Mass of 0.123 moles of these gases is:
O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong
N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong
SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible
CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong
Right answer is:
<h3>C 8.09 SO2 gas
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