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mojhsa [17]
2 years ago
3

The distance from san francisco to los angeles is approximately 385 miles. 1609 m = 1 mile. how many kilometers is this? use sig

nificant figures. do not enter “kilometers” as part of your answer.
Mathematics
1 answer:
Komok [63]2 years ago
5 0
In this question, you have already been given the distance (385 miles) but asked to answer with a different unit. Then to answer this question, you just need to convert the miles into kilometer. Note that a kilometer is 1000 meter so 1 mile would be 1.609 km.
The calculation would be:
385 miles * 1.609km/mile= 619.465km
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yanalaym [24]

Answer:1797.3


Step-by-step explanation:


3 0
2 years ago
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If R is the midpoint of QS , find QS (QR = 5x-3 and RS =21-x)
Finger [1]

Answer:

QS is 34

Step-by-step explanation:

We find x first. We set each side equal to each other to do so.

5x-3=21-x

6x=24

x=4

Next we find QS value. We add each side.

5x-3+21-x

4x+18

Then we plug in x to find numeric value.

4(4)+18

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The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in
Gnesinka [82]
First, determine the center of the circle by getting the midpoint of the points given for the circumference.
                    midpoint = ((0 + 0)/2, (3 + -4)/2)
                          midpoint (0, -0.5)
Then, we get the radius by determining the distance from either of the circumferential point to the center. 
                        radius = √(0 -  0)² + (3 +4)²  = 7
The equation for the circle would be,
                        x² + (y + 0.5)² = 7²
8 0
2 years ago
Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to
nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

\displaystyle L \approx f'(a)(x-a) + f(a)

We want to verify that the expression:

1-36x

Is the linear approximation for the function:

\displaystyle f(x) = \frac{1}{(1+9x)^4}

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)

Simplify. Hence:

\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}

Then the slope of the linear approximation at <em>x</em> = 0 will be:

\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36

And the value of the function at <em>x</em> = 0 is:

\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1

Thus, the linear approximation will be:

\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

\displaystyle \left| f(x) - L(x) \right | \leq 0.1

By definition:

\displaystyle -0.1\leq f(x) - L(x) \leq 0.1

Therefore:

\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

4 0
2 years ago
each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red
Vitek1552 [10]
It think it's 59/81.
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