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2 years ago

4

The ________ is an example of an active, continent-continent collision.

1 answer:

ycow [4]2 years ago

4 0

<span>The Continental collision is an example of an active, continent-continent collision. Is a process of plate tectonics by which two continental tectonic plates come in contact due to the tectonic forces that push them.</span>

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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th

Soloha48 [4]

Answer:

B= $\sqrt{65}$ ≅8.06

Explanation:

Using the Pythagorean theorem:

$C^{2}$ = $A^{2}$ + $B^{2}$

where C represents the length of the hypotenuse and A and B the lengths of the triangle's other two sides, we can find out the lenght of B assuming the value of the hypotenuse being 9 and A being 4.

$9^{2}$ = $4^{2}$ + $B^{2}$

81= 16+ $B^{2}$

81-16= $B^{2}$

B= $\sqrt{65}$ ≅8.06

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2 years ago

natali 33 [55]

Sonography is most likely because it has good resolution without radiation.

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2 years ago

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Air has a density of 1.3 kg/m³. Calculate the mass of 36 m³ of air in kilograms. Give your answer to 1 decimal place.

vredina [299]

Answer:

46.8 kg

Explanation:

Mass = (density)(volume)

= (1.3)(36)

<u>M</u><u>a</u><u>s</u><u>s</u><u> </u><u>=</u><u> </u><u>4</u><u>6</u><u>.</u><u>8</u><u> </u><u>k</u><u>g</u>

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2 years ago

A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 n directed at an angle of 15Â° below the

Kobotan [32]

Answer:

Acceleration of the crate is 0.362 m/s^2.

Explanation:

Given:

Mass of the box, m = 40 kg

Applied force, F = 15 N

Angle at which the force is applied, $(\theta)$ = 15°

We have to find the magnitude of the acceleration.

Let the acceleration be "a".

FBD is attached with where we can see the horizontal and vertical component of force.

⇒ $F_x=Fcos(\theta)$ and ⇒ $F_y=Fsin (\theta)$

⇒ $F_x=15cos(15)$ ⇒ $F_y=15sin (15)$

⇒ Applying concept of forces.

⇒ $\sum F_x=F_n_e_t =F-f$

⇒ $F_n_e_t =F-f$

⇒ $ma =F-f$ <em> ...Newtons second law Fnet = ma</em>

⇒ $a =\frac{F-f}{m}$

⇒ Plugging the values.

⇒ $a =\frac{15cos(15)-0}{40}$ <em>...f is the friction which is zero here.</em>

⇒ $a =\frac{14.48}{40}$

⇒ $a=0.362\ ms^-^2$

Magnitude of the acceleration of the crate is 0.362 m/s^2.

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2 years ago

Which amplitude of the following longitudinal waves has the greatest energy?

Rashid [163]

Which amplitude of the following longitudinal waves has the greatest energy?

amplitude = 10 cm; wavelength = 6 cm; period = 4 seconds

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2 years ago

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