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Flauer [41]
2 years ago
3

Which of the following statements best describes the work of Isaac Newton? A. It provided some of the earliest evidence in suppo

rt of a heliocentric theory. B. It led to a greater understanding of the relationship between pressure and volume. C. It focused on gravity and how forces acted on objects. D. It proposed that everything should be doubted until logic proved it true.
Chemistry
2 answers:
ZanzabumX [31]2 years ago
8 0

Answer:C

Explanation:

It defined a scientific method, although that method did not include the idea of a hypothesis.

VLD [36.1K]2 years ago
7 0
C is the answer................................
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What is the kinetic energy acquired by the electron in hydrogen atom, if it absorbs a light radiation of energy 1.08x101 J. (A)
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Explanation:

The given data is as follows.

            Energy of radiation absorbed by the electron in hydrogen atom = 1.08 \times 10^{-17} J

As energy is absorbed as a photon. Hence, frequency will be calculated will be as follows.

                                    E = h \nu

               1.08 \times 10^{-17} J = 6.626 \times 10^{-34} Js \times \nu

               \nu = 0.163 \times 10^{17} s^{-1}

or,                \nu = 1.63 \times 10^{16} s^{-1}    

It is known that,        \nu = \frac{c}{\lambda}

                1.63 \times 10^{16} s^{-1} = \frac{3 \times 10^{8} m/s}{\lambda}                  

                   \lambda = 1.84 \times 10^{-8} m

And, according to De-Broglie equation \lambda = \frac{h}{p}

as,        p = m \times \nu

So,          \lambda = \frac{h}{m \times \nu}

            m \times \nu = \frac{6.626 \times 10^{-34} Js}{1.84 \times 10^{-8} m}          

                             = 3.6 \times 10^{-26} J/m

Now, on squaring both the sides we get the following.

           (m \times \nu)^{2} = (3.6 \times 10^{-26} J/m)^{2}    

                              = 12.96 \times 10^{-52}  

               m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

where,   m = mass of electron

So,           m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}

                             = \frac{12.96 \times 10^{-52}}{9.1 \times 10^{-31}}

                                   = 1.42 \times 10^{-21} J

Since,  K.E = \frac{1}{2}m \nu^{2}

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A 0.200 M K 2SO 4 solution is produced by ________. dilution of 250.0 mL of 1.00 M K2SO4 to 1.00 L dissolving 43.6 g of K2SO4 in
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<u>Explanation</u>:

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where,

                      M1 = initial concentration

                      V1 = initial volume

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                      V2 = final volume

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