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Anika [276]
2 years ago
15

Please don't answer just to say "I don't know" Thank you

Mathematics
2 answers:
HACTEHA [7]2 years ago
7 0
M<6 = m<4  = 2x + 39              (vertical angles)
and m < 1  is also  = m<4       (corresponding angles)

Therefore  we have:-

2x + 39  = 8x + 15   Solving for x:-

2x - 8x = 15 - 39
-6x = - 24

x = 4

So the measure of <6 =  2(4) + 39  =  47 degrees.


AlekseyPX2 years ago
5 0

8x+15 = 2x+39

8x =2x+24

6x = 24

x = 24/6 = 4

 angle 4 = 2(4) +39 = 8+39 = 47

 angle 6 = angle 4

angle 6 = 47 degrees

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Eliza brought 3 pans of homemade fruit bars to school. Her classmates ate 7/12 of each pan. Eliza gave 1 whole pan of the leftov
-BARSIC- [3]
To solve this, you have to take 7/12 out of each pan first, so how to do that is to divide each pan into 1/12. So you did that, and all three pans equal 36/12. Great. Eliza has 36/12 fruit bars. 
Now, you see that the classmates at 7/12 out of EACH. To find that out, you just multiply 7/12 by 3 which is 21/12. Subtract 21/12 from 36/12 since the classmates ate 21/12 out of the total and you get 15/12.
Now she gave 1 pan to the secretaries, which is 12/12, so you subtract that from the 15/12 you have left over. That's 3/12.

And she brought 3/12 home. You can simplify that into 1/4.
3 0
2 years ago
PLEEEEEEEEEEASE HELP ASAP
Paraphin [41]

The answer is D. $431.04.

A semi-circle, is half a circle. You need to get the area of the semi-circle to get the price for the whole thing. Since the door is 34 inches, we can assume that the diameter of the window would be 34 inches.

Okay, since the area of the circle is: πr², we just need to divide the equation by 2. So you will have the equation:

A =\dfrac{\pi(r^{2})}{2}

Where:

π=3.14

r = radius

All we have is the diameter, and what we need is the radius. The radius is half of the diameter, so we divide the measurement of the diameter by two.

r=\dfrac{d}{2}\\\\ r=\dfrac{34in}{2}\\\\ r=17in

So now that we have the radius, let's put that into our area equation:

A=\dfrac{\pi(r^{2})}{2}\\ \\ A=\dfrac{(3.14)(17in^{2})}{2}\\ \\ 453.73in^{2}

The area of the semi-circle window is 453.73in².

Now let's get how much that would cost by multiplying the area by the price per square inch.

(453.73in^{2})(\dfrac{\$0.95}{in^{2}}) = \$431.04

The semi-circle would cost $431.04.

5 0
2 years ago
After four years of college, Erica has to start paying off all her student loans. Her first payment is due at the end of this mo
tatiyna

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]

M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84}  }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85

Therefore, the approximate monthly payment = $548.85

6 0
2 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x? StartRoot 1 plus-or-minus StartRoot 159 En
castortr0y [4]

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

We have the following equation:

4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0

We look for the roots:

x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}

We have to:

i ^ 2 = -1

So:

x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}

We have two imaginary roots:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

Answer:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

8 0
2 years ago
Read 2 more answers
A rectangle is placed around a semi circle as shown below. The width of the rectangle is 7yd. find the area of the shaded region
Nady [450]

Answer:

21.07 yd^2

Step-by-step explanation:

The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.

The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.

area of shaded region = area of rectangle - area of semicircle

A = LW - (1/2)(pi)r^2

A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2

A = 98 yd^2 - (1.57)(49 yd^2)

A = 98 yd^2 - 76.93 yd^2

A = 21.07 yd^2

4 0
2 years ago
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