<span>As it is descended from a vertical height h,
The lost Potential Energy = Mgh
The gained Kenetic Energy = (1/2)Mv^2; The rotational KE = (1/2)Jw^2
The angular speed w = speed/ Radius = v/R
So Rotational KE = (1/2)Jw^2 = (1/2)J(v/R)^2; J is moment of inertia
Now Mgh = (1/2)Mv^2 + (1/2)J(v/R)^2 => 2gh/v^2 = 1 + (J/MR^2)
As v = (5gh/4)^1/2, (J/MR^2) = 2gh/v^2 - 1 => (J/MR^2) = (8gh/5gh) - 1
so (J/MR^2) = 3/5 and therefore J = (3/5)MR^2.</span>
Answer:
5.59 m/s
Explanation:
We are given;
Mass = 110 kg
Initial velocity: u = 13.41 m/s
Force = 615 N
Time(t) = 1 s
Now, the formula for force is;
Force = mass x acceleration
Thus;
615 = 110 × acceleration
\Acceleration(a) = 615/110 = 5.591 m/s²
Now, using Newton's first law of motion, we can find acceleration (a). Thus;
v = u + at
v = 13.41 + (5.591 × 1)
v ≈ 19 m/s
So,the change in velocity is;
Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s
Answer:
Explanation:
Given two vectors as follows
E₁ = 13.5 i -12 j
E₂ = -7.4 i - 4.7 j
Resultant E = E₁ + E₂
= 13.5 i -12 j -7.4 i - 4.7 j
E = 6.1 i - 16.7 j
a ) X component of resultant = 6.1 N
b ) y component of resultant = -16.7 N
Magnitude of resultant = √ ( 6.1² + 16.7² )
= 17.75 N
d ) If θ be the required angle
tanθ = 16.7 / 6.1 = 2.73
θ = 70° .
counterclockwise = 360 - 70 = 290°
Explanation:
Below is an attachment containing the solution.
Answer:
he maximum frequency occurs when the denominator is minimum
f’= f₀ 
Explanation:
This is a doppler effect exercise, where the sound source is moving
f = fo 
when the source moves towards the observer
f ’=f_o 
Alexandrian source of the observer
the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects
f’= f₀
