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alexgriva [62]
2 years ago
14

Suppose a lab group reports a percent yield of sand of 105%. is it really possible to collect more sand than was originally pres

ent? what is a possible explanation for the “extra” product? do not consider calculation mistakes; think about the procedure used.
Chemistry
2 answers:
alina1380 [7]2 years ago
8 0

The maximum percent of the product should be 100 percent, so it was not possible to produce a higher than 100 percent yield like 105 percent mentioned in the question. If this happens, then it will be against the law of conservation of energy, that is, mass cannot be created.  

The enhanced mass may have got produced due to impurities. One of the reason is if one has rinsed the container and has left some amount of water. The water is not considered as a substrate, but it may enhance the weight of the result. There is also a probability that some reaction has taken place in the air, and generated liquid or solid substance, which would have increased the weight.  


Ymorist [56]2 years ago
6 0
<h2>Answer : The product is not completely dry or the containers that were used during the experiments were changed or got exchanged.</h2><h3>Explanation : </h3>

May be it is possible to collect more or some extra sand and get wrong results. During the filtration step may be that some of the water was soaked up by th sand. Also there is a possibility that sand was not fully dried before weighing. As it will give the incorrect mass, because of the weight changes.

During the experimental procedure, the scientist probably switched between containers from the initial one containers which has a different mass. May be during the filtration process the fine sand could have got trapped in the filtration cloth.

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suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
2 years ago
Read 2 more answers
Functional group and bond hybridization of vanillin
lana66690 [7]

Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group:  R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

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2 years ago
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Answer:

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Explanation:

All changes in heat, or energy, can be explained. Many of the reactions or changes we see in the world involve the conversion of energy. For example as we heat up a substance (eg. water), the amount of energy we put in should give us an exact temperature. However, this is a "perfect world" scenario, and does not occur in real life. Whenever heat is added to a substance like water, we always need to account for the energy that is going to be lost. For example, heat lost to evaporation or even the effect of measuring the temperature with a thermometer (the introduction of anything including a thermometer will affect the temperature).

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shtirl [24]
Water is the answer!
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2 years ago
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The combustion of propane is best described as an
GalinKa [24]
<h3><u>Answer;</u></h3>

Exothermic chemical reaction

<h3><u>Explanation;</u></h3>
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