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AveGali [126]
2 years ago
9

A beer maker is using yeast to make his favorite brew. how does yeast produce ethanol? through the reduction of acetaldehyde, de

rived from pyruvate through the oxidation of acetaldehyde, derived from pyruvate through the direct reduction of pyruvate, similar to lactic acid fermentation directly from the reduction of glucose through the reduction of lactic acid
Chemistry
1 answer:
Ludmilka [50]2 years ago
3 0
<span>In brewing, yeast is used for the fermentation step, which is the conversion of sugars into carbon dioxide gas (CO2) and ethyl alcohols (etOH). Yeast cells require complex enzymes for the fermentation of glucose based sugars into alcohols and carbon dioxide. The process involves both aerobic phases where yeast proliferate on a log scale followed by an anaerobic phase where oxygen is deprived and C02 maintains the gaseous environment. The second phase also clarifies the product allowing for the conversion of less savory alcohols into more palatable alcohols like ethyl alcohol.</span>
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If 10.0 liters of h2(g) at STP is heated to a temperature of 546 K, pressure remaining constant, the new volume of the gas will
Effectus [21]

Answer:

20L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 10L

Initial Temperature (T1) = stp = 273K

Final temperature (T2) = 546K

Final volume (V2) =..?

The new volume of the gas can be obtained by using the Charles' law equation as shown below:

V1/T1 = V2/T2

10/273 = V2/546

Cross multiply to express in linear form

273 x V2 = 10 x 546

Divide both side by 273

V2 = (10 x 546) / 273

V2 = 20L

Therefore, the new volume of the gas is 20L.

3 0
2 years ago
Hector claims that a single sodium ion and a single oxygen ion do not bond together to form a stable binary ionic compound. Is h
levacccp [35]

Answer:

C

Explanation:

Looking at the periodic table, we can see that sodium is in group 1, so a sodium ion would be Na⁺, with a charge of +1. Oxygen is in group 16, so an oxygen ion would be O²⁻, with a charge of -2.

A compound formed only by a single sodium ion and a single oxygen ion would thus have a charge of -1, and in order to have a stable ionic compound its charge must be zero.

8 0
2 years ago
Read 2 more answers
calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
2 years ago
Which of these was not proposed by john dalton in 1805?
wel

Answer:

Atoms are made of protons, neutrons and electrons.

Explanation:

The Dalton's atomic theory was an early attempt at describing the properties of atoms. It stipulated that atoms were the smallest indivisible particle of a substance. Chemical reactions occur as a result of a combination or separation of atoms. Atoms of the same element are exactly alike and differ from atoms of other elements. Atoms can neither be created nor destroyed.

As time went on, modern scientific evidence began to modify the original postulates of the Dalton's atomic theory. It was not postulated in 1805 that atoms were composed of subatomic particles; electrons, neutrons and protons. Dalton's theory held the atom to be 'indivisible'. However in 1897, JJ Thompson discovered the electron. Subsequently, the proton and neutrons were discovered. This shows that the atom in itself consisted of even smaller particles.

3 0
2 years ago
In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 27.0 ∘C . You identified that the ideal pressure
dimaraw [331]

Answer : The percent difference between the ideal and real gas is, 4.06 %.

Explanation : Given,

Ideal pressure (true value) = 49.3 atm

Real pressure (measured value) = 47.3 atm

The formula used to calculate percent difference is :

Percent difference = \frac{\text{True value - Measured value}}{\text{True value}} \times 100

Percent difference = \frac{(49.3- 47.3)atm}{49.3atm}\times 100

Percent difference = 4.06 %

Therefore, the percent difference between the ideal and real gas is, 4.06 %.

4 0
2 years ago
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