Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
Answer:
(x,y) = (5.8,-0.4)
Step-by-step explanation:
1.) x + 2y = 4.2 - 2y = 5
2.) { x + 2y =5
{ 4.2 - 2y = 5
3.) { x + 2y = 5
{ y = -0.4
4.) x + 2x ( -4.0 ) = 5
5.) x= 5.8 ( a possible solution )
6.) ( x , y ) = ( 5.8 , -0.4 ) check to the solution
7.) 5.8 + 2 x ( -0.4 ) = 4.2 - 2 x ( -0.4 ) = 5
8.) 5 =5 =5
It translates to
which solves to
after dividing both sides by 78. This means n is equal to 4 or it can be larger than 4.
Answer:
Step-by-step explanation:
Total cost for the three nights
Total_3 = $298.17 + 3*u
Where <em>u </em>represents the unknown fees for a single day
To find the daily cost, we divide the previous equation by three
Daily cost = ($298.17 + 3*u)/3
Daily cost = ($99.39 + u)
So, if we create an inequality for the daily cost
Let x = Daily cost
x > $99.39
She will pay more than $99.39 per night
Answer:
<em>Mean of the sample = 27.83</em>
<em> The variance of the the sample = 106.96</em>
<em> </em><em>Standard deviation of the sample = 10.34</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given random sample of six employees
x 26 32 29 16 45 19
mean of the sample

Mean of the given data = 27.83
<u>Step(ii):-</u>
<u>Given data</u>
x : 26 32 29 16 45 19
x - x⁻ : -1.83 4.17 1.17 -11.83 17.17 -8.83
(x - x⁻)² : 3.3489 17.3889 1.3689 139.9489 294.80 77.9689
∑ (x-x⁻)² = 534.8245
Given sample size 'n' =6
The variance of given data
S² = ∑(x-x⁻)² / n-1

The variance of the given sample = 106.9649
<u> Step(iii):-</u>
Standard deviation of the given data

Standard deviation of the sample = 10.3423