Answer:
Empirical formula is Li₂CO₃.
Explanation:
Percentage of oxygen= 65.0%
Percentage of lithium = 18.7%
Percentage of carbon= 16.3%
Empirical formula = ?
Solution:
Number of gram atoms of C = 16.3/12 = 1.4
Number of gram atoms of Li = 18.7/6.94 = 2.7
Number of gram atoms of O = 65.0/ 16 = 4.1
Atomic ratio:
Li : C : O
2.7/1.4 : 1.4/1.4 : 4.1/1.4
2 : 1 : 3
Li : C : O = 2 : 1 : 3
Empirical formula is Li₂CO₃.
The total energy in a system due to the temperature and pressure per unit mass in that system is known as specific enthalpy. It is used in thermodynamic equations when one desires to know the energy for a given single unit mass of a component.
Specific enthalpy is calculated by the equation:
H = U + PV
in the given case, Specific volume = 4.684 cm³/g = 149.888 cm³/g moles = 149.888 × 10⁻³ J/g moles
Specific internal energy (U) is 1706 J/mol and pressure is 41.64.
H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules
= 2428 joules / mole
Answer:
The other signal that would indicate the presence of a C= C bond appears close to 3100 
.
Explanation:
Bands that appear above 3000 are often unsaturation diagnoses suggest. The band at 3000-
3100 is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.
Acetaminophen as a chemical formula of C8H9NO2. The molar
masses are:
C8H9NO2 = 151.163 g/mol
C = 12 g/mol
H = 1 g/mol
N = 14 g/mol
O = 16 g/mol
<span>TO get the mass percent, simply multiply the molar mass of
each elements with the number of the
element divide by the molar mass of acetaminophen, that is:</span>
%C = [(12 * 8) / 151.163] * 100% = 63.50%
%H = [(1 * 9) / 151.163] * 100% = 5.954%
%N = [(14 * 1) / 151.163] * 100% = 9.262%
<span>%O = [(16 * 2) / 151.163] * 100% = 21.17% </span>
