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Dmitriy789 [7]
2 years ago
14

What is the absolute structural necessity for an alcohol to be oxidized with chromium trioxide?

Chemistry
1 answer:
4vir4ik [10]2 years ago
8 0
The alcohol being oxidized must not be a tertiary alcohol.

A tertiary alcohol is one in which the -OH group is attached to a carbon atom which is attached to three other carbon atoms. This "closes off" the alcohol group and prevents the formation of oxidation products. This is the reason why tertiary alcohols do not undergo oxidation in mild conditions.
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Ethene is classified as an unsaturated hydrocarbon because it has _____.
WARRIOR [948]

the answer is c i think.


3 0
2 years ago
Read 2 more answers
Select the valid ways to make an ammonia/ammonium buffer for use in the laboratory. Mix equal volumes of 1 M NH3 and 0.01 M NH 4
mrs_skeptik [129]

Answer:

The answer is "Option b and Option c".

Explanation:

This buffer is a buffer of ammonia and ammonium ion. Thus it requires the solution NH_3 \ \ and \ \ NH_4^{+}.

In point 1:

The solution containing NH_3 \ \ and \ \ NH_4^{+} at 1M concentration would be given by mixing the two solutions. Thus, this buffer is a legitimate route.

In point 2:

It gives the ions you want but they are not the same.

In point 3:

1 M NH_3 and 1 MHCl volume would not produce the same NH_3 \ \ and \ \ NH_4^{+} concentrations. Therefore, this buffer isn't a valid route.

In point 4:

Some 1 M NH_3 volume and half HCl . This offers the same rate as half.

7 0
1 year ago
Four balloons, each with a mass of 10.0 g, are inflated to a volume of 20.0 L, each with a different gas: helium, neon, carbon m
weeeeeb [17]
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
4) m(NO) = 0,82 mol ·30 g/mol = 24,6 g.
d(NO) = 34,6 g ÷ 20 L = 1,73 g/L.
6 0
1 year ago
Read 2 more answers
Consider the two facts below:
OLEGan [10]

Answer:

A. There is more dissolved oxygen in colder waters than in warm water.

D. If ocean temperature rise, then the risk to the fish population increases.

Explanation:

Conclusion that can be drawn from the two facts stated above:

*Dissolved oxygen is essential nutrient for fish survival in their aquatic habitat.

*Dissolved oxygen would decrease as the temperature of aquatic habit rises, and vice versa.

*Fishes, therefore, would thrive best in colder waters than warmer waters.

The following are scenarios that can be explained by the facts given and conclusions arrived:

A. There is more dissolved oxygen in colder waters than in warm water (solubility of gases decreases with increase in temperature)

D. If ocean temperature rise, then the risk to the fish population increases (fishes will thrive best in colder waters where dissolved oxygen is readily available).

4 0
1 year ago
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs
Mars2501 [29]
The answer is (4) Add enough solvent to 30.0 g of solute to make 1.0 L solution. The molarity is calculated using volume of the solution. When solute dissolving, the total volume will change. So the final volume of solution need to be 1.0 L.
4 0
1 year ago
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