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Ber [7]
2 years ago
12

The general reaction of carboxylic acid derivatives is __________.

Chemistry
1 answer:
Ivan2 years ago
7 0
Nucleophilic acyl substitution
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Analyze the example of this door knob wheel and axle.
bulgar [2K]

Answer:

28

Explanation:

Velocity ratio= Radius of wheel/radius of axle

Radius of wheel= 4.125 inches

Radius of axle= 0.125 inches

Velocity ratio = 4.125/0.125 = 33

Then;

Efficiency = mechanical advantage/velocity ratio × 100

Since the efficiency of the system = 85%

85 = mechanical advantage/33 × 100

Mechanical advantage = 85 × 33/100 = 28

4 0
2 years ago
Analyze: The first shell can hold a maximum of two electrons. How does this explain the valence of hydrogen
chubhunter [2.5K]

Answer:

See explanation

Explanation:

Hydrogen has a valency of +1 or -1. Its electronic configuration is 1s1.

The 1s sub-level (first shell) is known to hold two electrons. This means that hydrogen may either loose this one electron in the 1s level to yield H^+ or accept another electron into this 1s level to form H^- (the hydride ion).

The formation of the hydride ion completes the 1s orbital.

4 0
2 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
shutvik [7]

Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

  • 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃

  • x = 0.1875 × 2 / 3 mol SO₃ =  0.125 mol SO₃

<u>5) Yield in grams:</u>

  • mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol =  10.0 g

<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
6 0
2 years ago
A 63.5 g sample of an unidentified metal absorbs 355 ) of heat when its temperature changes
insens350 [35]

0.208 is the specific heat capacity of the metal.

Explanation:

Given:

mass (m)  = 63.5 grams 0R 0.0635 kg

Heat absorbed (q) = 355 Joules

Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K

cp (specific heat capacity) = ?

the formula used for heat absorbed  and to calculate specific heat capacity of a substance will be calculated by using the equation:

q = mc Δ T

c = \frac{q}{mΔ T}

c = \frac{355}{63.5X 268.59}

 = 0.208 J/gm K

specific heat capacity of 0.208 J/gm K

The specific heat capacity is defined as  the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.

 

5 0
2 years ago
If 0.278g of argon dissolves in 1.5 l of water at 62 bar, what quantity of argon will dissolve at 78 bar
irinina [24]
When P1/P2 = C1/C2

and C is the molarity which = moles/volume

so, P1/P2 = [(mass1/mw)/volume] / [(mass2/mw)/volume]

P1/P2 = (mass1/mw)/1.5L / (mass2/mw)/1.5L 

so, Mw and 1.5 L will cancel out:

∴P1/P2 = mass1 / mass2

∴ mass 2 = mass1*(P2 / P1)

                = 0.278g * (78 bar / 62 bar)

                = 0.35 g

∴ the quantity of argon that will dissolve at 78 bar = 0.35 g


5 0
2 years ago
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