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Gennadij [26K]
2 years ago
11

Dorian buys 2 pounds of almonds for $21.98 and 3 pounds of dried apricots for $26.25. Which is less expensive per pound? how muc

h less expensive? complete the tables of equivalent ratios to help you solve.
almonds cost wright (lb) 2 dried apricots cost $26.25 weight (lb)
Mathematics
2 answers:
Bogdan [553]2 years ago
7 0
Apricots is 8.75 per pound and is less expensive than almonds per pound (10.99). To find how much less expensive you subtract apricots from almonds. 10.99-8.75= 2.24.

Please vote my answer brainliest. thanks!
marusya05 [52]2 years ago
5 0

Answer:

Apricots are less expensive by $2.24 per pound.

Step-by-step explanation:

The cost of 2 pound of almonds for = $21.98

The cost of 1 pound of almonds = \frac{21.98}{2}

                                                     = $10.99

The cost of 3 pounds dried apricots for = $26.25

The cost of 1 pound dried apricots = \frac{26.25}{3}

                                                          = $8.75

Difference in cost per pound = 10.99 - 8.75

                                                  = $2.24

Dried apricots are $2.24 per pound less expensive.

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311 students prefer sushi

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Let

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Substitute the equation B in equation A and solve for y

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2 years ago
Let x stand for the length of an individual screw. 100 screws were sampled at a time. The population mean is 2.5 inches and the
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Answer:

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8 0
2 years ago
A university surveyed recent graduates of the English department for their starting salaries. Four hundred graduates returned th
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Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.

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Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245

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2 years ago
Which row in the chart correctly identifies the functions of structures A, B, and C? *
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2 years ago
Let ​ f(x)=x2+5x−36 ​. Enter the x-intercepts of the quadratic function in the boxes.
san4es73 [151]
Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-5*x-(36)=0 

Step by step solution:<span> Step 1:</span> Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-5x-36</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is 1.
The middle term is, <span> -5x </span> its coefficient is  - 5.
The last term, "the constant", is <span> -36 </span>

Step-1: Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2: Find two factors of  -36  whose sum equals the coefficient of the middle term, which is - 5.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9</span><span>     -9   +   4   =   -5   That's it</span></span>


Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  4 
                     <span>x2 - 9x</span> + 4x - 36

Step-4: Add up the first 2 terms, pulling out like factors :
                    x • (x-9)
              Add up the last 2 terms, pulling out common factors :
                    4 • (x-9)
Step-5: Add up the four terms of step 4 :
                    (x+4)  •  (x-9)
             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x + 4) • (x - 9) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     x = -4 

Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-9 = 0<span> 

 </span>Add  9  to both sides of the equation :<span> 
 </span>                     x = 9 

6 0
2 years ago
Read 2 more answers
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