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2 years ago

Within an integrated circuit, each wafer is cut into sections, which

Physics

2 answers:

fiasKO [112]2 years ago

7 0

The final answer is B hope its helps

photoshop1234 [79]2 years ago

5 0

The answer is D.

An integrated circuit (IC) is a circuit that’s built up by depositing a series of thin layers of film on a base material. The base material is usually a thin disk or wafer of germanium or silicon about one inch in diameter. After the desired number of layers of film has been deposited on the base in succession, the surface of the wafer is divided into many tiny squares. Then, each square is converted by certain precise processes into a complex electronic circuit with many components. Finally, each wafer is cut into sections so that each section carries a single circuit, and each section is placed in an individual case.

Reference: Pages 136/137

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A 20~\mu F20 μF capacitor has previously charged up to contain a total charge of Q = 100~\mu CQ=100 μC on it. The capacitor is t

sertanlavr [38]

Explanation:

The given data is as follows.

C = $20 \times 10^{-6} F$

R = $100 \times 10^{3}$ ohm

$Q_{o} = 100 \times 10^{-6}$ C

Q = $13.5 \times 10^{-6} C$

Formula to calculate the time is as follows.

$Q_{t} = Q_{o} [e^{\frac{-t}{\tau}]$

$13.5 \times 10^{-6} = 100 \times 10^{-6} [e^{\frac{-t}{2}}]$

0.135 = $e^{\frac{-t}{2}}$

$e^{\frac{t}{2}} = \frac{1}{0.135}$

= 7.407

$\frac{t}{2} = ln (7.407)$

t = 4.00 s

Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.

4 0

2 years ago

A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic

Sunny_sXe [5.5K]

Answer:

Magnetic field will be ZERO at the given position

Explanation:

As we know that the magnetic field due to moving charge is given as

$B = \frac{\mu_0 qv sin\theta}{4\pi r^2}$

so here we know that for the direction of magnetic field we will use

$\hat B = \hat v \times \hat r$

so we have

$\hat B = \hat i \times (\hat i + 0\hat j + 0\hat k)$

so magnetic field must be ZERO

So whenever charge is moving along the same direction where the position vector is given then magnetic field will be zero

3 0

2 years ago

Consider two circular metal wire loops each carrying the same current I as shown below. In what r... Consider two circular metal

NeX [460]

Answer:

1) The magnetic field outside the loop is zero.

In region III the magnetic fields due to the two wire loops point in the opposite direction andhence cancel each other. Therefore the magnetic field is zero in region I, III and V

The diagram is attached