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2 years ago

Within an integrated circuit, each wafer is cut into sections, which

Physics

2 answers:

fiasKO [112]2 years ago

7 0

The final answer is B hope its helps

photoshop1234 [79]2 years ago

5 0

The answer is D.

An integrated circuit (IC) is a circuit that’s built up by depositing a series of thin layers of film on a base material. The base material is usually a thin disk or wafer of germanium or silicon about one inch in diameter. After the desired number of layers of film has been deposited on the base in succession, the surface of the wafer is divided into many tiny squares. Then, each square is converted by certain precise processes into a complex electronic circuit with many components. Finally, each wafer is cut into sections so that each section carries a single circuit, and each section is placed in an individual case.

Reference: Pages 136/137

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wheel rotates from rest with constant angular acceleration. Part A If it rotates through 8.00 revolutions in the first 2.50 s, h

Alex73 [517]

Answer:

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

Explanation:

Given;

wheel rotates from rest with constant angular acceleration.

Initial angular speed v = 0

Time t = 2.50

Distance x = 8 rev

Applying equation of motion;

x = vt +0.5at^2 ........1

Since v = 0

x = 0.5at^2

making a the subject of formula;

a = x/0.5t^2 = 2x/t^2

a = angular acceleration

t = time taken

x = angular distance

Substituting the values;

a = 2(8)/2.5^2

a = 2.56 rev/s^2

velocity at t = 2.50

v1 = a×t = 2.56×2.50 = 6.4 rev/s

Through the next 5 second;

t2 = 5 seconds

a2 = 2.56 rev/s^2

v2 = 6.4 rev/s

From equation 1;

x = vt +0.5at^2

Substituting the values;

x2 = 6.4(5) + 0.5×2.56×5^2

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

5 0

2 years ago

Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne

slega [8]

Answer:

$\epsilon = 2.96 \times 10^{-11} \ V$

Explanation:

given,

magnetic field strength = 1.40 ✕ 10⁻³ T

frequency of oscillation = 60 Hz

diameter of RBC = 7.5 μm

EMF = ?

$\epsilon = NBA\omega$

$\epsilon = NB(\pi\ r^2)\ (2\pi f)$

$\epsilon = NB(\pi\ (\dfrac{d}{2})^2)\ (2\pi f)$

$\epsilon = (1)\ 1.4 \times 10^{-3}(\pi\ (\dfrac{7.5 \times 10^{-6}}{2})^2)\ (2\pi\times 60)$

$\epsilon = 2.96 \times 10^{-11} \ V$

maximum emf that can generate around the perimeter of the cell $\epsilon = 2.96 \times 10^{-11} \ V$

5 0

2 years ago

Which of the following four circuit diagrams best represents the experiment described in this problem?

Valentin [98]

We don't see any circuit diagrams.

This worries us for a few seconds, until we realize that we don't know anything about the experiment described in the problem either, so we don't have to worry about it at all.

6 0

2 years ago

A solid element that is malleable' a good conductor of electricity, and reacts with oxygen is classified as a

Finger [1]

1) metal
Even though metalloids are also conductors of heat and electricity, malleable they are not as good as metals.
Metals are very good conductors of electricity and heat. They are also very hard to touch. Noble gases and non metals are the exact opposite in physical and chemical properties. Metals readily react with oxygen.

5 0

2 years ago

You should have observed that there are some frequencies where the output is stronger than the input. Discuss how that is even p

nydimaria [60]

Answer:

w = √ 1 / CL

This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence

Explanation:

This problem refers to electrical circuits, the circuits where this phenomenon occurs are series RLC circuits, where the resistor, the capacitor and the inductance are placed in series.

In these circuits the impedance is

X = √ (R² + ( $X_{C}$ - $X_{L}$ )² )

where Xc and XL is the capacitive and inductive impedance, respectively

X_{C} = 1 / wC

X_{L} = wL

From this expression we can see that for the resonance frequency

X_{C} = X_{L}

the impedance of the circuit is minimal, therefore the current and voltage are maximum and an increase in signal intensity is observed.

This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence

V = IR

Since the contribution of the two other components is canceled, this occurs for

X_{C} = X_{L}

1 / wC = w L

w = √ 1 / CL

6 0

2 years ago