Each face of cabinet 413s is in the shape of a rectangle. What is the volume of model 413s in cubic feet
2 answers:
Hopefully this is the question you are talking about!
They want us to find the volume of model 413S in ft³
This isnt tough!
change the side measurements from Inches to Feet
12 in = 1 ft
so therefore:
24 in = 2 ft
72 in = 6 ft
18 in = 1.5 ft
Volume of a cuboid is:
Area of base × height of cuboid
V = 2 ft × 6 ft ×1.5 ft
= 18 ft³
Volume of the cabinet (Model 413S) is 18 ft³
They want us to find the volume of model 413S in ft³
This isnt tough!
change the side measurements from Inches to Feet
12 in = 1 ft
so therefore:
24 in = 2 ft
72 in = 6 ft
18 in = 1.5 ft
Volume of a cuboid is:
Area of base × height of cuboid
V = 2 ft × 6 ft ×1.5 ft
= 18 ft³
Volume of the cabinet (Model 413S) is 18 ft³
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I found a similar problem to your problem here, which is shown in the attached picture. So, from the picture, we have to find the equation for the red line. All we have to do is find two points of the line. That would be: Point 1(2,0) and Point 2(-2,3). The general equation would be:
y - y₁ = (y₂-y₁)/(x₂ - x₁) * (x - x₁)
Substituting the coordinates to the equation,
y - 0 = (3-0)/(-2 - 2) * (x - 2)
y = -3(x -2)/4
Rearranging,
<em>4y = -3x + 6 or 4y + 3x = 6</em>
y - y₁ = (y₂-y₁)/(x₂ - x₁) * (x - x₁)
Substituting the coordinates to the equation,
y - 0 = (3-0)/(-2 - 2) * (x - 2)
y = -3(x -2)/4
Rearranging,
<em>4y = -3x + 6 or 4y + 3x = 6</em>
Answer:
0.00
Step-by-step explanation:
If the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed, to calculate the probability that a test taker scores at least 1600 on the test, we should first to calculate the z-score related to 1600. This z-score is , then, we are seeking P(Z > 2.95), where Z is normally distributed with mean 0 and standard deviation 1. Therefore, P(Z > 2.95) = 0.00