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natta225 [31]
2 years ago
12

Lola has 4 orange juice containers. each container is 5/8 full. Lola claims to have a total of 2 1/2 gallons of orange juice in

the 4 containers. which one of these statements must be true for her claim to be correct?
Each Container has a capacity of 5/8 gallon

Each container has a capacity of a 1 gallon

Each container has a capacity of 2 1/2 gallons

Each container has a capacity of 8 gallons
Mathematics
1 answer:
IrinaK [193]2 years ago
7 0

Each container has a capacity of 5/8 gallon.

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Below are summary statistics for the sizes (in acres) of some local vineyards. Using the summary statistics, complete parts (a)
rjkz [21]

Answer:

option B

Step-by-step explanation:

The symmetric distribution have close or approximate values of median and mean. In the given scenario mean is 48.5 and median is 33. We can see that the both values significantly differs. Also, given mean is greater than median(48.5>33) . Thus, the distribution is positively skewed and not symmetrical.

Hence, the distribution is skewed because mean and median significantly differ from each other.

3 0
2 years ago
According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –
SVETLANKA909090 [29]

We have to identify the function which has the same set of potential rational roots as the function g(x)= 3x^5-2x^4+9x^3-x^2+12.

Firstly, we will find the rational roots of the given function.

Let 'p' be the factors of 12

So, p= \pm 1, \pm 2, \pm 3, \pm 4, \pm 6

Let 'q' be the factors of 3

So, q=\pm 1, \pm 3

So, the rational roots are given by \frac{p}{q} which are as:

\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}.

Consider the first function given in part A.

f(x) = 3x^5-2x^4-9x^3+x^2-12

Here also, Let 'p' be the factors of 12

So, p= \pm 1, \pm 2, \pm 3, \pm 4, \pm 6

Let 'q' be the factors of 3

So, q=\pm 1, \pm 3

So, the rational roots are given by \frac{p}{q} which are as:

\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}.

Therefore, this equation has same rational roots of the given function.

Option A is the correct answer.

4 0
2 years ago
Read 2 more answers
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
the population of Ketcham high school has been decreasing by 5 % per year.if it's population is currently 2600 which of the foll
kap26 [50]
5% = .05
2600 x .05 = 130
130 x 2 = 260
2600 - 260 = 2340

The population will be 2340 people.
6 0
2 years ago
A hike starts at an elevation 13 4/5 feet below sea level and ends at an elevation that is 1,542 feet higher . How high was the
Montano1993 [528]
The answer is (B) 1,528 1/5
7 0
2 years ago
Read 2 more answers
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