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Rama09 [41]
2 years ago
8

A 4.0-n puck is traveling at 3.0 m/s. it strikes an 8.0-n puck, which is stationary. the two pucks stick together. their common

final speed is:
Physics
1 answer:
Natalka [10]2 years ago
3 0
<span>1.0 m/s Momentum = mass x velocity Total Momentum before any collision = total momentum afterwards 4.0 x 3.0= 12 :g x momentum before (x g because using weight) Afterwards, if the velocity of the two joined is v then we get: 'momentum x g'=12v so 12v=12 so v=1m/s</span>
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Listed following are locations and times at which different phases of the moon are visible from earth’s northern hemisphere. mat
Airida [17]
For the answer tot he questions above, I know this one.
The answers are
 <span>-sets 2-3 hours after the sun sets - waxing crescent 
-occurs about 3 days before the new moon - waning crescent 
-occurs 14 days after the new moon - full moon 
-rises at about the time the sun sets - full moon 
-visible due south at midnight - full moon 
-visible near eastern horizon just before sunrise waning crescent 
-visible near western horizon about an hour after sunset waxing crescent</span>
7 0
2 years ago
In an electric furnace used for refining steel, the temperature is monitored by measuring the radiant power emitted through a sm
stiks02 [169]

Answer: 3.7×10¹²watts

Explanation:

Radiation is one of the mode of heat transfer and modes differs from each other based on their medium of heat transfer. Radiation is a process of transferring heat energy from one point to another without heating the intervening medium (no material medium is required).

According to Stefan's law of radiation, the rate of emission of radiant energy is directly proportional to the fourth power of its absolute temperature.

Mathematically, R = eAT⁴

e is constant of proportionality called emissivity. Emissivity varies depending on the type of body being considered.

For the question, we are considering black body and emissivity of black body is 1 being a perfect body.

A is the area of the body

T is the absolute temperature

e = 1

A = 0.5cm²

T = 1650°C

Rate of radiation = 1×0.5×1650⁴

= 3.7×10¹²watts.

The hole will therefore radiate 3.7×10¹²watts

3 0
2 years ago
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to thenext handhold. A 9.3kggibbon has
Mumz [18]

Upward force provided by the branch is 260 N

<u>Explanation:</u>

Given -

Mass of Gibbon, m = 9.3 kg

Length of the branch, r = 0.6 m

Speed of the movement, v = 3.3 m/s

Upward force, T = ?

The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.

Therefore,

F net = T - mg

F net = ma = mv²/r

Thus,

T = mv²/r + mg

T = m ( v²/r + g)

T = 9.3 [ ( 3.3)² / 0.6 + 9.8]

T = 259.9 N ≈ 260 N

Therefore, upward force provided by the branch is 260 N

5 0
2 years ago
Suppose you first walk 12.0 m in a direction 20 owest of north and then 20.0 m in a direction 40.0osouth of west. How far are yo
alexgriva [62]

Answer:

R=19.5m

\theta = 4.65° S of W

Explanation:

Refer the attached fig.

displacement  of the x and y components

x-component displacement is (R_{x}) = A_{x}+B_{x}

= A \sin(20°) + B \cos(40°)

= -12.0\sin(20°) + 20.0\cos(40°)

= -19.425m

x-component displacement is (R_{y}) = A_{y}+ B_{y}

=  A \cos(20°) - B \sin(40°)

= 12.0\cos(20°) - 20.0\sin(40°)

= -1.579

resultant displacement

∴

R = \sqrt{R_{x}^{2} +R_{y}^{2} }  }

=\sqrt{(-19.425)^{2}+(-1.579)^{2}  }

=19.5m

\theta = \tan^{-1}\left | \frac{R_{x}}{R_{y}} \right |

\theta = \tan^{-1}\left | \frac{1.579}{19.425} \right |

\theta = 4.65° S of W

6 0
2 years ago
A small object with mass 0.200 kg swings back and forth on the lower end of a light rope that is 3.00 m long. The upper end of t
Alex787 [66]

Answer:

= 6.8 N

Explanation:

T = mg + ma

T = tension, N

m = mass, kg

g = gravitational force, 9.8 m/s2²

a = acceleration, m/s²

a =( 8.5²) / 3

a = 24.08

T = mg + ma

T = m (g + a)

T = 0.2 ( 9.8 + 24.08)

T = 0.2 ( 33.88)

T = 6.776N

≅ 6.8N

5 0
2 years ago
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