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dalvyx [7]
2 years ago
11

An animal shelter has a ratio of dogs to cats that's 3:2. If there are 30 cats at the shelter, how many

Mathematics
2 answers:
viktelen [127]2 years ago
8 0

An animal shelter has a ratio of dogs to cats that's 3:2. If there are 30 cats at the shelter, 45 dogs are there . 3/2 = x/30 , x= 30*3/2 =45


lisov135 [29]2 years ago
3 0
<span>In the question "An animal shelter has a ratio of dogs to cats that's 3:2. If there are 30 cats at the shelter, how many dogs are there" the correct answer is 45 (option D). To solve the problem, let the number of dogs be x, then dogs / cats = 3 / 2 = x / 30. i.e. 2x = 3(30) = 90. x = 90 / 2 = 45. Therefore, there are 45 dogs in the animal shelter.</span>
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A decimal number changed to 23.7 after it was rounded. Give a decimal number that is less than 23.7 and another that is greater
mrs_skeptik [129]

Two <em>possible answers</em> are:

23.65 and 23.72.

Explanation:

For the first number, 23.65, we are rounding to the tenths place. 23.65 itself is smaller than 23.7. Looking behind the tenths place, the digit behind it is 5. This means we round the tenths place up; this becomes 23.7.

23.72 is larger than 23.7. We will round it to the tenths place as well. Looking behind the tenths place, we have a 2; this means we "round down." This means leave the 7 as it is and drop the other digits behind it. This gives us 23.7.

3 0
2 years ago
Read 2 more answers
The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda
blondinia [14]

Answer:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

\mu = 514 , \sigma =40

For this case we can use the Chebysev theorem who states that "At least 1 -\frac{1}{k^2} of the values lies between \mu -k\sigma and \mu +k\sigma"

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

4 0
2 years ago
What is the greatest common factor of 60x4y7, 45x5y5, and 75x3y? 5xy 15x3y 45x3y5 75x5y7
Pepsi [2]
I believe it’s 5xy since all the numbers are factors of five and since each number contains the variables xy.
6 0
2 years ago
Read 2 more answers
A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2
aev [14]

Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

Force = mv^2/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

7 0
2 years ago
Which expressions are equivalent to {22c + 33d}22c+33d22, c, plus, 33, d?
kotegsom [21]
A
 (-2c-3d) (- 11) (- 2c-3d) (- 11) left parenthesis, minus, 2, c, minus, 3, d, right parenthesis, left parenthesis, minus, 11, right parenthesis
 C
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1 left parenthesis, 66, c, plus, 99, d, right parenthesis, dot, start fraction, 1, divided by, 3, end fraction
<span> E
 11\cdot(2c+3d)11⋅(2c+3d)11, dot, left parenthesis, 2, c, plus, 3, d, right parenthesis
</span> answer
 (-2c-3d) (- 11) = 22c + 33d
 (66c + 99d) * 1/3 = 22c + 33d
 11 * ( 2c+3d) = 22c + 33d
4 0
2 years ago
Read 2 more answers
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