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Naddika [18.5K]
2 years ago
3

Why is it necessary to remove unreacted sodium hydroxide from the soap before using it on the skin?

Chemistry
1 answer:
VashaNatasha [74]2 years ago
8 0
Unreacted Sodium Hydroxide requires protected wearable like gloves, face mask, and eye protector before handling because it is a strong irritant and may harm the skin and eyes when came into contact. If ingested, it may affect the gastrointestinal system.That is why it is very important to remove, carefully, the sodium hydroxide in the soap.
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Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, [\text{H}^{+}] = 10^{-\text{pH}}, where [\text{H}^{+}] is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w, where [\text{OH}^{-}] the concentration of hydroxide ions and \text{K}_w is the dissociation constant of water.

\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3} at 0.10 MPa and 25 °C. As a result, [\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}.

5 0
2 years ago
The combustion of propane gas is used to fuel barbeque grills. If 4.65 moles of propane, C3H8, are burned in a grilling session,
Varvara68 [4.7K]

Answer:

<h3>moles of carbon dioxide=13.95mol</h3>

Explanation:

First wrie down the balance chemical reaction:

C_3H_8(g) + 5 O_2(g) \rightarrow 3 CO_2(g) + 4 H_2O(l)

Combustion reaction: The reacion in which hydrocarbon is burnt in the presence of oxygen gas and it releases heat and this reaction exothermic because heat of cumbustion is negative.

eg. burning of methane

By using unitry method,

From the above balanced reaction it is clearly that,

from 1 mole of propane 3 moles of carbon dioxide is formed

there fore,

from 4.65 mole of propane 3 \times 4.65 moles of carbon dioxide will form

moles of carbon dioxide=13.95mol

8 0
2 years ago
Arrange the following in order of increasing boiling point: RbCl, CH3Cl, CH3OH, CH4. A. CH3OH &lt; CH4 &lt; CH3Cl &lt; RbCl B. R
rosijanka [135]

Answer:

E. CH₄ < CH₃Cl < CH₃OH < RbCl

Explanation:

The molecule with the stronger intermolecular forces will have the higher boiling point.

The order of strength of intermolecular forces (strongest first) is

  • Ion-Ion
  • Hydrogen bonding
  • Dipole-dipole
  • London dispersion

RbCl is a compound of a metal and a nonmetal. It is an ionic compound, so it has the highest boiling point.

CH₃Cl has a C-Cl polar covalent bond. It has dipole-dipole forces, so it has the second lowest boiling point.

CH₃OH has an O-H bond. It has hydrogen bonding, so it has the second highest boiling point.

CH₄ has nonpolar covalent C-H bonds. It has only nonpolar bonds, so the only attractive forces are London dispersion forces. It has the lowest boiling point.

Thus, the order of increasing boiling points is

CH₄ < CH₃Cl < CH₃OH < RbCl

4 0
2 years ago
A student conducting a calorimetry investigation determines a negative ∆H. What does the negative value indicate about the react
lawyer [7]

Answer:

a

Explanation:

correct

5 0
2 years ago
Calculate the mass of MNO2 needed to produce 25.0 g of Cl2
Vedmedyk [2.9K]
I will solve this question assuming the reaction equation look like this:
<span>MnO2 + 4 HCl ---> MnCl2 + Cl2 + 2 H2O. 
</span>
For every one molecule of MnO2 used, there will be one molecule of Cl2 formed. If the molecular mass of MnO2 is 87g/mol and molecular mass of Cl2 is <span> 73.0 g/mol, the mass of MnO2 needed would be:
Cl mass/Cl molecular mass * MnO2 molecular mass=
25g/ (73g/mol) * (87g/mol) * 1/1= 29.8 grams</span>
7 0
2 years ago
Read 2 more answers
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