Answer:Hydrogen is placed such because it exhibits some similar characteristics of both group1 and group VII elements.
Explanation:
The reason why hydrogen is similar to group 1 metals:
#It has same valence electron and inorder achieve octet state it can lose that electron and forms H+ ion
#It acts as a good reducing agent similar to group1 metals
#It can also halides
Similarity to halogens:
#hydrogen can also gain one electron to gain noble gas configuration. It can combine with other non metals to form molecules with covalent bonding.
#It exists as diatomin molecule,H2
#Have the same electronegativity nature
#its reaction with other metal
In a chemical reaction,
the limiting reagent is the chemical being used up while the excess reactant is
the chemical left after the reaction process.
Before calculating the limiting
and excess reactant, it is important to balance the equation first by stoichiometry.
C25N3H30Cl + NaOH = C25N3H30OH + NaCl
Since the reaction is already balanced, we can now identify which
is the limiting and excess reagent.
First, we need to determine the number of moles of each chemical
in the equation. This is crucial for determining the limiting and excess reagent.
<span>Assuming that there is the
same amount of solution X for each reactant</span>
1.0 M NaOH ( X ) = 1.0
moles NaOH
1.00 x 10-5 M C25N3H30Cl
( X ) = 1.00 x 10-5 moles C25N3H30Cl
<span>The result showed that the
crystal violet has lesser amount than NaOH. Thus, the limiting reactant in this
chemical reaction is crystal violet and the excess reactant is NaOH.</span>
Explanation:
Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.
Mass of sample (CuSO4 * nH2O)
= 152.00g - 128.10g = 23.90g.
Mass of water loss during heating
= 152.00g - 147.60g = 4.40g.
Molar mass of H2O = 18g/mol
Moles of H2O in sample
= 4.40g / (18g/mol) = 0.244mol.
Mass of anhydrous sample (CuSO4)
= 23.90g - 4.40g = 19.50g
Molar mass of CuSO4 = 159.61g/mol
Moles of CuSO4 in sample
= 19.50g / (159.61g/mol) = 0.122mol.
Since mole ratio of CuSO4 to H2O
= 0.122mol : 0.244mol = 1:2, n = 2.
Hence we have CuSO4 * 2H2O.
Answer: C
I hope this helped you
It matches the universal pH indicator and is indicating the proper pH
