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NNADVOKAT [17]
2 years ago
8

A pencil is rolled off a table of height 0.35 m. If it has a horizontal speed of 2.1 m/s, how long does it take the pencil to re

ach the ground?
Physics
1 answer:
KatRina [158]2 years ago
8 0
1) Kind of motion: horizontal launch

2) Formulas:

y = yo - Vo,y * t -  g*t^2 / 2

yo = 0.35 m

g = 9.8 m/s^2

Vo,y = 0 (this is the pencil does not have initial vertical speed)

The time to reach the ground does not depend on the initial horizontal speed

3) Calculations

y = 0

=> 0 = 0.35 m - 9.8 m/s^2 * t^2 / 2

=> t^2 = 0.35 m * 2 / 9.8 m/s^2 = 0.0714 s^2

=> t = √(0.0714 s^2) = 0.27 s

Answer: 0.27 s
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Alik [6]

Answer:

The correct answer to the following question will be Option A (moment arm; pivot point).

Explanation:

  • The moment arm seems to be the duration seen between joint as well as the force section trying to act mostly on the joint. Each joint that is already implicated in the workout seems to have a momentary arm.
  • The moment arm extends this same distance from either the pivot point to just the position of that same pressure exerted.
  • The pivotal point seems to be the technical indicators required to fully measure the appropriate demand trends alongside different time-frames.

The other three choices are not related to the given situation. So that option A is the appropriate choice.

7 0
2 years ago
Keisha looks out the window from a tall building at her friend Monique standing on the ground, 8.3 m away from the side of the b
Salsk061 [2.6K]

Answer:

Explanation:

GIVEN DATA:

Distance between keisha and her friend 8.3 m

angle made by keisha toside building 30 degree

height of her friend monique is 1.5 m

from the figure

\Delta ACB

tan 30 = \frac{8.3}{h}

h= \frac{8.3}{tan 30} = 14.376 m

therefore

height of keisha is = h  + 1.5 m

                               = 14.376 + 1.5

= 15.876 \simeq 16 m

therefore option c is correct

5 0
2 years ago
Length of two cylinders are measured to be L1 = 5.62 +/- 0.01cm and L2 = 4.34 +/- 0.02cm.
zavuch27 [327]

Answer:

Explanation:

Just look at the figure

7 0
2 years ago
Two wires are used to suspend a sign that weighs 500 N. The two wires make an angle of 100° between each other. If each wire is
vaieri [72.5K]
1) draw a diagram.
2) label diagram. (split the 100 degrees into 50, (which is right down the middle)  to make a right angle triangle.)
3) since its a free body diagram, the forces known must be labelled. (force of gravity). this shows that the straight vertical line of the right angle triangle is Fg (force gravity). label it.
4) use trigonometry. rearrange the equation to solve for what needs to be known.
 
angles known: 50 (split 100 in half to make a right angle triangle), 90 (since its right angle), and 40 (180-90-50 = 40)

sides known: vertical lined up with the 90 degree angle. Fg. --> fg=mg=500N x 9.81m/s^2 = 4905N

use formula: sin or cos 

i used sin. sin(40) = 4905 / ?
- times '?' on both sides. :  sin(40) x '?' = 4905
-divide both sides by sin(40):  '?' = 4905/ sin(40)
--> Solve.

8 0
2 years ago
carbon-14 has a half-life of approximately 5,700 years. a fossil shell contain 25% of the original amount of its carbon-14. appr
denis23 [38]

The half-life equation m=m_{0} (\frac{1}{2})^n in which <em>n </em>is equal to the number of half-lives that have passed can be altered to solve for <em>n.</em>

<em>n = \frac{log(\frac{m}{m_{0}} )}{log(\frac{1}{2})}</em>

<em>\frac{log(\frac{.25}{1} )}{log(\frac{1}{2})} = 2</em>

Then, the number of half-lives that passed can be multiplied by the length of a half-life to find the total time.

<em>2 * 5700 =  </em>11400 yr

3 0
2 years ago
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