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saw5 [17]
2 years ago
7

Which of the answer choices is a true statement? Select all that apply. Metallic elements usually exist as molecules, combining

with atoms of themselves. Metallic elements can exist on their own as individual atoms. Nonmetals usually exist as molecules, combining with atoms of themselves. Nonmetals can exist on their own as individual atoms.
Physics
1 answer:
Pani-rosa [81]2 years ago
6 0

Metallic elements can exist on their own as individual atoms.

Nonmetals usually exist as molecules, combining with atoms of themselves.

Nonmetals can exist on their own as individual atoms.

Explanation:

Metallic elements can exist on their own as individual atoms without combining with another atom. They are stable that way. For example gold, copper, and silver.

Non-metals are usually found as molecules in combined states. The molecules are bounded to each other through covalent bonds. Examples are oxygen gas, nitrogen gas e.t.c. When the two atoms combine, they share their electrons to for homonuclear molecules.

Non-metals like the noble gases exists on their own as individual atoms. They are mono-atomic gases and are stable in nature.

learn more:

Metals and non - metals brainly.com/question/2758034

#learnwithBrainly

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A spherical drop of water carrying a charge of 30 pC has a potential of 500 V at its surface (with V 0 at infinity). (a) What is
Delicious77 [7]

Answer:

A. 5.4 * 10^(-4) m

B. 500V

Explanation:

A. Electric potential, V is given as:

V = kq/r

This means that radius, r is

r = kq/V

r = (9 * 10^9 * 30 * 10^(-12))/500

r = (270 * 10^(-3))/500

r = 5.4 * 10^(-4) m

B. Now the radius is doubled and the charge is doubled,

V = (9 * 10^9 * 2 * 30 * 10^(-12))/(2 * 5.4 * 10^(-4) * 2)

V = 500V

7 0
2 years ago
A skydiver finds that she speeds up when she holds her arms close to her body. What does this do?
ArbitrLikvidat [17]

D. Reduces the force of air resistance

7 0
2 years ago
Read 2 more answers
A two-resistor voltage divider employing a 2-k? and a 3-k? resistor is connected to a 5-V ground-referenced power supply to prov
vesna_86 [32]

Answer:

circuit sketched in first attached image.

Second attached image is for calculating the equivalent output resistance

Explanation:

For calculating the output voltage with regarding the first image.

Vout = Vin \frac{R_{2}}{R_{2}+R_{1}}

Vout = 5 \frac{2000}{5000}[/[tex][tex]Vout = 5 \frac{2000}{5000}\\Vout = 5 \frac{2}{5} = 2 V

For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.

so.

R_{out} = R_{2} || R_{1}\\R_{out} = 2000||3000 = \frac{2000*3000}{2000+3000} = 1200

Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.  

if the -5% is applied to both resistors the Voltage is still 5V because the quotient  has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:

Vout = 5 \frac{1900}{4900}\\Vout = 5 \frac{19}{49} = 1.93 V

Vout = 5 \frac{2100}{5100}\\Vout = 5 \frac{21}{51} = 2.05 V

R_{out} = R_{2} || R_{1}\\R_{out} = 1900||2850= \frac{1900*2850}{1900+2850} = 1140

R_{out} = R_{2} || R_{1}\\R_{out} = 2100||3150 = \frac{2100*3150 }{2100+3150 } = 1260

so.

V_{out} = {1.93,2.05}V\\R_{1} = {1900,2100}\\R_{2} = {2850,3150}\\R_{out} = {1140,1260}

4 0
2 years ago
Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. Wha
MArishka [77]

Answer:

P = 1.64 \times 10^4 Watt

Explanation:

Here we know that the glider is accelerated uniformly from rest to final speed of 25.7 m/s in total distance of d = 46.9 m

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v_f = 25.7 m/s

v_i = 0

d = 46.9

so for uniformly accelerated motion we have

d = \frac{v_f + v_i}{2} t

46.9 = \frac{25.7 + 0}{2}t

t = 3.65 s

now we will find the total work done given as change in kinetic energy

W = \frac{1}{2}mv^2

W = \frac{1}{2}(181)(25.7^2)

W = 5.97 \times 10^4 J

now power is given as

P = \frac{W}{t}

P = \frac{5.97 \times 10^4}{3.65}

P = 1.64 \times 10^4 Watt

6 0
2 years ago
Think about it: suppose a meteorite collided head-on with mars and becomes buried under mars's surface. what would be the elasti
Ket [755]

Answer:

Perfectly inelastic collision

Explanation:

There are two types of collision.

1. Elastic collision : When the momentum of the system and the kinetic energy of the system is conserved, the collision is said to be elastic. For example, the collision of two atoms or molecules are considered to be elastic collision.

2. Inelastic collision: When the momentum  the system is conserved but the kinetic energy is not conserved, the collision is said to be inelastic. For example, collision of a ball with the mud.

For a perfectly elastic collision, the two bodies stick together after collision.

Here, the meteorite collide with the Mars and buried inside it, the collision is said to be perfectly inelastic. here the kinetic energy of a body lost completely during the collision.

4 0
2 years ago
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