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Agata [3.3K]
2 years ago
14

Have you done any factoring with variables? Which property (Commutative, Distributive, or Associative) do you think is most invo

lved in factoring? Do you think a polynomial can be a factor of another polynomial? Answer in full sentences.
Mathematics
2 answers:
vazorg [7]2 years ago
7 0
Idk how im supposed to answer this or whatevs bu
yes i have done factoring with variables.
distrubutive is the most involved in factoring method as i can tell.
i dont think ive studied this before or i mightve forgoten but im sure a polynomial can be factored into another one.
and yea. hope this helped in sum way
ASHA 777 [7]2 years ago
3 0

⇒x²y³=x*x*y*y*y=x*y*x*y*y=y*x*y*x*y--Writing factors in another way

⇒xy²z²=x*y*y*z*z=y*x*z*y*z=z*x*y*x*y*z---Writing factors in another way.

⇒xy+xy²=xy(1+y)

⇒y²z²-yzx=yz(yz-x)

Here ,we have used law of indices first, then used Commutativity , Associativity and Distributivity to factor Polynomial.

1.\rightarrow x^{a+b}=x^a \times x^b\\\\2.\rightarrow x \times y=y \times x----\text{Commutative Property}\\\\3.\rightarrow x \times (y \times z)= (x \times y) \times z=(x \times z) \times y---\text{Associaitive Property}

⇒Distributive Property of Multiplication with respect to addition and Subtraction

  →a×(b+c)=a×b+a×c

 → a×(b-c)=a×b-a×c

⇒Yes, A polynomial can be factor of another polynomial.

For Example:

⇒ x²-a², has two factors equal to , (x+a) and (x-a), where , x²-a², is a quadratic polynomial and two of it's factors are ,(x+a) and (x-a) which is also a polynomial of degree 1.

 

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Answer:

<u>option 1</u>

Step-by-step explanation:

The question is as shown in the attached figure.

From the figure, we can deduce that:

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But it is required to know " How can the triangles be proven similar by the SSS similarity theorem? "

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With the help of the previous corresponding angles.

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5 0
1 year ago
Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x
spin [16.1K]

we have

y-6x-9=0

Step 1

<u>Clear the variable y</u>

y-6x-9=0

Adds (6x+9) both sides

y-6x-9+(6x+9)=0+(6x+9)

y=(6x+9)

Step 2

<u>Convert in function notation</u>

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therefore

<u>the answer is</u>

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