The answer is 75.
Let's look at your problem shall we:
Odd number: It should end with the numbers 1,3,5,7, and 9.
The number is less than 100: It should be from the number 1-99
Sum of digits: 12
Multiple of 15: 15, 30, 45, 60, 75, and 90.
We can rule out 30, 60, and 90 because they are even.
1+5 = 6; 4+5=9; 7+5 = 12
You are left with 75.
Answer:
the probability that randomly selected applicants over 10 years of experience is 0.6791
Step-by-step explanation:
The computation of the probability that randomly selected applicants over 10 years of experience is as follows:
Total would be
= 187 have 10 + years experience
Now
P(graduate | 10+) = (graduate and 10+ years experience) ÷ (10 + years of experience)
= 127 ÷ 187
= 0.6791
Hence, the probability that randomly selected applicants over 10 years of experience is 0.6791
F(1)=4(1+1+7)-2(1)+8-4
f(1)=36+2
f(1)=38
f(2)=4(2+2+7)-2(2)+8-4
f(2)=44
Answer: 0.813
Step-by-step explanation:
Let A be the event describes the number of residents believed that the amount of violent television programming had increased over the past 10 years.
& B be the event describes the number of residents believed that the amount of violent television programming had decreased over the past 10 years.
Given : n(A)=721 ; n(B)=454 ; n(A∩B)=362
We know that ,

i.e. 
Also, the total number of U.S. residents surveyed n(S)= 1,000
Then, the proportion of the 1,000 U.S. residents believed that either the amount of violent programming had increased or the overall quality of programming had decreased over the past 10 years will be :-

Hence, the required answer = 0.813