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weqwewe [10]
2 years ago
8

What is the value of y in the equation 5x + 2y =20 , when x = 0.3

Mathematics
2 answers:
Burka [1]2 years ago
8 0

To solve this equation, we must substitute in 0.3 for the value of x and then solve the equation for y.

5(0.3) + 2y = 20

To simplify, we begin by multiplying the two numbers on the left side of the equation.

1.5 + 2y = 20

Next, we should subtract 1.5 from both sides of the equation to get the variable term alone.

2y = 18.5

Finally, we should divide both sides of the equation by 2 in order to get the variable y completely alone on the left side of the equation.

y = 9.25

Therefore, the value of y is 9.25.

Hope this helps!

Alex_Xolod [135]2 years ago
8 0
5x + 2y = 20
5 X 0.3 + 2y = 20
1.5 + 2y = 20
2y = 20 - 1.5
2y = 18.5
y = 18.5/2
y = 9.25

The value of y is 9.25
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On a coordinate plane, 5 trapezoids are shown. Trapezoid L M N P is in quadrant 2 and has points (negative 5, 1), (negative 5, 4
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The answer is figure C

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Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
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Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
2 years ago
A cardboard carrying box has the dimensions shown below. How many square inches of
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

5x6 = 30x2 = 60

6x10 = 60

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4x6=24 (dont need to divide by two since theres two triangles)

24+60+60+200= 344

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