They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.
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Answer:
The flux through the surface of the cube is 
Solution:
As per the question:
Edge of the cube, a = 8.0 cm = 
Volume Charge density, 
Now,
To calculate the electric flux:
(1)
where
= electric flux
= permittivity of free space
Volume Charge density for the given case is given by the formula:
(2)
Volume of cube, 
Thus

Thus from eqn (2), the total charge is given by:


Now, substitute the value of 'q' in eqn (1):

Answer:
The torque on the wrench is 4.188 Nm
Explanation:
Let r = xi + yj where is the distance of the applied force to the origin.
Since x = 18 cm = 0.18 cm and y = 5.5 cm = 0.055 cm,
r = 0.18i + 0.055j
The applied force f = 88i - 23j
The torque τ = r × F
So, τ = r × F = (0.18i + 0.055j) × (88i - 23j) = 0.18i × 88i + 0.18i × -23j + 0.055j × 88i + 0.055j × -23j
= (0.18 × 88)i × i + (0.18 × -23)i × j + (0.055 × 88)j × i + (0.055 × -22)j × j
= (0.18 × 88) × 0 + (0.18 × -23) × k + (0.055 × 88) × (-k) + (0.055 × -22) × 0 since i × i = 0, j × j = 0, i × j = k and j × i = -k
= 0 - 4.14k + 0.0484(-k) + 0
= -4.14k - 0.0484k
= -4.1884k Nm
≅ -4.188k Nm
So, the torque on the wrench is 4.188 Nm
Answer:
James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down
Explanation:
Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards
so here we can say
Upwards force = downwards Force + weight of snow
while if we find the other force which is acting downwards
then for that force we can say that net torque must be balanced
so here we have

so here we have

so here we can say that upward force by which we push up is always more than the downwards force
Answer:
The current is 
Explanation:
From the question we are told that
The radius of the kite string is 
The distance it extended upward is 
The thickness of the water layer is 
The resistivity is 
The potential difference is 
Generally the cross sectional area of the water layer is mathematically represented as

Here r is mathematically represented as
![r = [(R + d ) - R]](https://tex.z-dn.net/?f=r%20%3D%20%20%5B%28R%20%2B%20d%20%29%20-%20R%5D)
=> ![r = [(0.00202 + 0.000506 ) - 0.00202]](https://tex.z-dn.net/?f=r%20%3D%20%20%5B%280.00202%20%2B%20%200.000506%20%29%20-%200.00202%5D)
=> 
=>
=>
Generally the resistance of the water is mathematically represented as

=> 
=> 
Generally the current is mathematically represented as

=> 
=> 