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Natasha_Volkova [10]
2 years ago
14

A snail is travelling at 0.4 millimetres per second. Work out the snail's speed in metres per hour. Show clear working out witho

ut a calculator
Mathematics
1 answer:
GrogVix [38]2 years ago
6 0
60 sec=1 min  so 3600sec in a hour  .4mm=0.0004meters in a hours time the snail would have moved 1440mm or 
  (1.44mph)                                                                             
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if two points are given,then exactly one line can be drawn through those two points.which geometry term does the statement repre
lubasha [3.4K]

Answer:

This is a postulate which states that through any two points, there is exactly one line.

Step-by-step explanation:

A postulate is a statement that is assumed true without proof.

5 0
2 years ago
Read 2 more answers
the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the
ivanzaharov [21]

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

7 0
1 year ago
An airliner carries 150 passengers and has doors with a height of 78 in. Heights of men are normally distributed with a mean of
iogann1982 [59]

Answer:

Step-by-step explanation:

x, height of men is N(69, 2.8)

Sample size n =150

Hence sample std dev = \frac{2.8}{\sqrt{150} } =0.229

Hence Z score = \frac{x-69}{0.229}

A) Prob that a random man from 150  can fit without bending

= P(X<78) = P(Z<3.214)=1.0000

B) n =75

Sample std dev = \frac{2.8}{\sqrt{75} } =0.3233

P(X bar <72) = P(Z<9.28) = 1.00

C) Prob of B is more relevent because average male passengers  would be more relevant than a single person

(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.

3 0
2 years ago
The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.3t^4 + 1100 where t is the time
Montano1993 [528]
The maximum occurs when the derivative of the function is equal to zero.
P(t)=-0.3t^{4}+130t+1100 \\ P'(t)=-1.2t^{3}+130 \\ 0=-1.2t^{3}+130 \\ 1.2t^{3}=130 \\ t^{3}= \frac{325}{3}  \\ t=4.76702
Then evaluate the function for that time to find the maximum population.
P(t)=-0.3t^{4}+130t \\ P(4.76702)=-0.3*4.76702^{4}+130*4.76702+1100 \\ P(4.76702)=1564.79201
Depending on the teacher, the "correct" answer will either be the exact decimal answer or the greatest integer of that value since you cannot have part of a rabbit.
7 0
2 years ago
Two towns, A and B, are connected by a road. At sunrise, Pat begins biking from A to B along this road, while simultaneously Dan
Gnoma [55]

Answer:

The answer is "4.5"

Step-by-step explanation:

Given value:

\text{time = 11:15 PM}

formula:

\to t^2=\frac{pt}{D} \times \frac{Dt}{P}\\\\_{where}\\\\\text {t= time = noon - sunrise}\\\\\text{p= pat's speed}\\\\\text{D= Dana's speed}\\

\to t^2= 11.25 \times 5\\\\

      = 56.25\\\\

\to t= 7.5

if the sunrise value is =12

\to sunrise = 12- 7.5

                 = 4.5

3 0
2 years ago
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