Question

What is the approximate radius of a 112 48 cd nucleus?

Answer 1

What is it comparing it to?

2√3 = 1.26 times as large 

Answer 2

Answer:

radius of a $^{112}Cd_{12}$ nucleus is 5.784×$10^{-15}$ meters

Step-by-step explanation:

Since radius of a nucleus is measured by the formula

R = $R_{0}(A)^{\frac{1}{3} }$

Where $R_{0}$ is the average radius of a nucleus. This radius varies with the size of nucleons.

In this formula A = number of nucleons = (Number of protons + neutrons)

For element Cd number of nucleons = 112

and $R_{0}$ = 1.2×$10^{-15}$

Now we put these values in the given formula

R = $1.2\times 10^{-15}\times(112)^{\frac{1}{3}}$

  =$1.2\times 10^{-15}\times4.82$

  = 5.784×$10^{-15}$ meters

Therefore, radius of a $^{112}Cd_{12}$ nucleus is 5.784×$10^{-15}$ meters