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docker41 [41]
2 years ago
12

Claire bought 180 candies and 140 pens for goody bags for her birthday. What is the largest number of goody bags that Claire can

make so that each goody bag has the same number of candies and the same number of pens?
Mathematics
2 answers:
Kruka [31]2 years ago
6 0
Wouldn't it be 140 bags with one of each in it; unless you need to use all the candies?
Kitty [74]2 years ago
6 0

Answer: 20

Step-by-step explanation:

Given : Claire bought 180 candies and 140 pens for goody bags for her birthday.

To find : The largest number of goody bags that Claire can make so that each goody bag has the same number of candies and the same number of pens ( such that no pens or candies left).

So we find the GCF ( Greatest common factor ) or Number of candies and Number of pens.

i.e. we need to find GCF of 180 and 140 .

Prime factorization of 180 = 2\times2\times3\times3\times5

Prime factorization of 140 =2\times2\times7\times5

The greatest common factor of 180 & 140 = 2\times2\times5=20

∴ Claire can make 20 goody bags so that each goody bag has the same number of candies and the same number of pens.

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Chester, the dog, loves to eat treats. He has eaten twice as many today as yesterday. He has eaten a total of 15 dog treats in b
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Answer:

The equations are:

T = 2Y and T + 2Y = 15

Step-by-step explanation:

Given

Represent bones eaten Today with T and yesterday with Y

Required

Write the equation

In the first statement, we have that:

T = 2Y

Reading further; In the second statement

T + 2Y = 15

Hence, the equations are:

T = 2Y and T + 2Y = 15

Solving further:

Substitute 2Y for  T in the second equation

2Y + 2Y = 15

4Y = 15

Divide both sides by 4

Y = \frac{15}{4}

Y = 3.75

Recall that

T = 2Y

T= 2 * 3.75

T= 7.5

7 0
1 year ago
Three brothers share one video game system at their home. In total, they are allowed to play for one half hour each day. If each
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Answer:

45 min.

Step-by-step explanation:

1 1/2 hours = 90 min.

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4 0
2 years ago
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MaRussiya [10]
you have to add 90 +90 3 times then theres your answer :)



6 0
2 years ago
Suppose 1000 people enter a chess tournament. Use a rooted tree model of the tournament to determine how many games must be play
Vlada [557]

Answer: 999 games

Step-by-step explanation:

There are many ways to illustrate the rooted tree model to calculate the number of games that must be played until only one player is left who has not lost.

We could go about this manually. Though this would be somewhat tedious, I have done it and attached it to this answer. Note that when the number of players is odd, an extra game has to be played to ensure that all entrants at that round of the tournament have played at least one game at that round. Note that there is no limit on the number of games a player can play; the only condition is that a player is eliminated once the player loses.

The sum of the figures in the third column is 999.

We could also use the formula for rooted trees to calculate the number of games that would be played.

i=\frac{l - 1}{m - 1}

where i is the number of "internal nodes," which represents the number of games played for an "<em>m</em>-ary" tree, which is the number of players involved in each game and l is known as "the number of leaves," in this case, the number of players.

The number of players is 1000 and each game involves 2 players. Therefore, the number of games played, i, is given by

i=\frac{l - 1}{m - 1} = i=\frac{1000 - 1}{2 - 1} = \frac{999}{1} =999

7 0
1 year ago
What is 63.4 divided by 20
Zanzabum
317 is the answer you are looking for.
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