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2 years ago

How will adding different flavors of kool-aid to water affect the water's boiling point for kids?

Chemistry

2 answers:

Digiron [165]2 years ago

6 0

Answer:

Kool aid affects the boiling point of water due to its colligative properties.

Explanation:

Colligative properties are the properties of solutions that depend on the number of dispersed particles and are independent of the nature of the solute particles.

Because of the colligative properties, the effects of solute (kool-aid) alter the physical properties of water. An example of this is that kool aid raises the boiling temperature of water. This is because Kool-aid contains citric acid, calcium phosphate, maltodextrin and salt. All of these substances have high boiling points, so when mixed with water they increase it boiling point.

Harlamova29_29 [7]2 years ago

4 0

Adding different flavors of Kool-Aid to water will change boiling point, Kool-Aid increase the water's boiling point because ingredients of Kool-Aid are: citric acid, calcium phosphate, maltodextrin, salt, that substances increase boiling temperature of water.
Kool-Aid is flavored drink mix.

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Answer:

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2 years ago

If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products

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Answer:

For a: The equilibrium mixture contains primarily reactants.

For b: The equilibrium mixture contains primarily products.

Explanation:

There are 3 conditions:

When $K_{eq}>1$ ; the reaction is product favored.
When $K_{eq}$ ; the reaction is reactant favored.
When $K_{e}=1$ ; the reaction is in equilibrium.

For the given chemical reactions:

For a:

The chemical equation follows:

$HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}$

The expression of $K_{eq}$ for above reaction follows:

$K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}$

As, $K_{eq}$ , the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

For b:

The chemical equation follows:

$H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}$

The expression of $K_{eq}$ for above reaction follows:

$K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}$

As, $K_{eq}>1$ , the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

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2 years ago

Kaia, a chemical engineering graduate, has documented all titration procedures in her project report. She refers to this report

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Answer:

The correct option is;

d. Explicit knowledge

Explanation:

Explicit knowledge is the knowledge that can be easily articulated documented stored in a retrieval system accesses, transmitted and shared with others

Tacit knowledge is the skill developed by an individual based on actual experience such that such knowledge comprise of both facts and perspectives

Hence explicit knowledge and tacit knowledge are complementary

The operations performed by Kaia include documentation, storing in a retrieval system (her project report) and accessing what she documented, this is an example of explicit knowledge.

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C
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2 years ago

Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G

AnnyKZ [126]

1) Chemical equation

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) molar ratios

1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3)2 : 2 mol Ag

3) Convert 12. 83 * 10^23 atoms of Cu in moles

12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Use the proportions

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) Use the atomic mass of silver to convert 4.262 mol in grams

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Answer: 459.9 g

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2 years ago