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muminat
2 years ago
14

Your blood contains many dissolved solids. What do you think could be done if you needed to remove the water from a sample of bl

ood in order to study the solids that remained? (4 points) Think about what processes remove water from watery foods, solutions, or objects.
Chemistry
1 answer:
bezimeni [28]2 years ago
8 0
An apparatus called a centrifuge is used to separate solids from the aqueous portion of blood. A sample of the blood is transferred to a small vial or test tube and this vessel is then placed into the centrifuge. The machine works by rotating the sample around a fixed axis, spinning it in a circle, and this results in a strong force being applied to the sample that is perpendicular to the axis of the spin. This force is called the centripetal force and this centripetal acceleration causes the most dense particles in the blood to move outward in the radial direction. This results in the less dense materials being displaced by the more dense materials. Once the sample vessel is retrieved from the centrifuge, the sample will be separated into layers, such that the solids are found at the bottom of the vessel. The less dense materials such as the water will be found at the top of the vessel.
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A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated
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Answer:

The empiricial formula of the compound is BaO2

Explanation:

<u>Step 1:</u> Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

<u>Step 2: </u>Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

<u>Step 3</u>: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

<u>Step 4:</u> Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

<u>Step 5:</u> Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

<u>Step 6:</u> Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

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2 years ago
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