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photoshop1234 [79]
1 year ago
8

What phases (solid, liquid, gas) are present in the unlighted candle? In the burning candle? Which phase appears to take part in

the chemical reaction?
Chemistry
2 answers:
PSYCHO15rus [73]1 year ago
8 0
Only the solid phase.
When lit all three phases of matter are present, solid, liquid and gas. The candle itself is still solid. But liquid wax pools under the flame. And the flame itself is releasing gases consisting mostly of water vapor and carbon dioxide. Many consider the flame is in another state of matter, the plasma state. It's a high energy state of matter exhibited by stars, flames and lightning.
Feliz [49]1 year ago
5 0

Answer:

As explained below.

Explanation:

  • In an unlighted, the solid phase can be seen when it's in solid shape and not ignited when it starts to burn it's said to have entered into the liquid phase or wax phase.
  • The liquid phase is to be part of the chemical reaction because the chemical reactions are seen when it is lit with the presence of oxygen and the last phase of gas is given out in the form of flames of fire upon burning as to give out carbon dioxide and ash.

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you push a friend sitting on a swing. she has a mass of 50kg and accelerates at a rate of 4 m/s2. find the force you exerted
Hoochie [10]
Mass of the friend sitting on the swing = 50 kg
Rate of acceleration = 4 m/s^2
The above information's are already given in the question. We need to utilize these information's in such a manner that the answer to the question can be determined easily.
We already know that
Force = Mass * acceleration.
This formula has to be used to find the force exerted.
Then
Force exerted = Mass of the friend * Acceleration
                       = (50 * 4) kg m/s^2
                       = 200 Newton
So the force exerted by me is 200 Newton. I hope the explanation and the procedure is clear to you and you are satisfied with it.
6 0
2 years ago
Read 2 more answers
A 2.80 g sample of Al reacts with 4.15 g sample of Cl2 according to the equation shown below.
solong [7]

Answer:

Mass = 5.33 g

Explanation:

Given data:

Mass of Al = 2.80 g

Mass of Cl₂ = 4.15 g

Theoretical yield of AlCl₃ = ?

Solution:

Chemical equation:

2Al  +  3Cl₂        →       2AlCl₃

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 2.80 g/ 27 g/mol

Number of moles = 0.10 mol

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.15 g/71 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of AlCl₃ with Al and Cl₂.

                    Cl₂           :        AlCl₃

                    3              :          2

                   0.06         :        2/3×0.06 = 0.04

                   Al             :        AlCl₃

                     2            :          2

                   0.10         :        0.10

Number of moles of AlCl₃ produced by chlorine are less so it will be limiting reactant.

Mass of AlCl₃:Theoretical yield

Mass = number of moles ×molar mass

Mass = 0.04 mol × 133.34 g/mol

Mass = 5.33 g

4 0
1 year ago
a 0.5678 of KHP required 26.64cm³ of NaOH to complete neutralization.calculate the molarity of the NaOH solution​
vladimir2022 [97]

Answer:

Explanation:

0.5678 G        X GRAMS

KHC8H4O4 + NaOH = NaKC8H4O4 + H2O

1 MOL               1 MOL

0.5678G X 204G/MOL = 0.00278 MOL KHC8H4O4

0.00278 MOL KHC8H4O4 X 1 MOLE NaOH/1 MOLE  KHC8H4O4=0.00278 MOL NaOH

0.00278 MOL NaOH/26.26ml=0.106 molar

4 0
1 year ago
A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constantpressure calorimeter that has a heat capa
bogdanovich [222]

Explanation:

The given data is as follows.

         V_{1} = 85.0 ml,        M_{1} = 0.9 M

         V_{2} = 85.0 ml,        M_{1} = 0.9 M

Hence, number of moles of HCl and KOH will be the same because both the solutions have same volume and molarity.

So,     No. of moles = Molarity × Volume

                                = 0.9 M \times 0.085 L        (as 1 L = 1000 ml so, 85 ml = 0.085 L)

                                = 0.076 mol

As 1 mole gives 56.2 kJ/mol of heat of neutralization. Hence, calculate the heat of neutralization given by 0.076 moles as follows.

              56.2 kJ/mol \times 0.076 mol

                    = 4.271 kJ

or,                 = 4271 J     (as 1 kJ = 1000 J)

Therefore,    heat released = - heat of gained by calorimeter

Since, it is given that density of the solution is similar to the density of water which is 1 g/ml.

Hence,     mass of HCl = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Similarly,    mass of KOH = = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Hence, total mass of the solution = 85 g + 85 g

                                                        = 170 g

Also,                   q = mC \Delta T

                     4271 J = 170 g \times 325 J/^{o}C \times (T_{f} - 18.24)^{o}C    

                     0.0773 = T_{f} - 18.24

                    T_{f} = 18.317^{o}C  

Thus, we can conclude that final temperature of the mixed solution is 18.317^{o}C.

6 0
2 years ago
Determine the total number of moles of ions in 40.0 ml of a 0.345 m solution of the strong electrolyte mgcl2
Sedbober [7]
A strong electrolyte like MgCl2 dissociates completely as per the following reaction:

MgCl_2 ----\ \textgreater \   Mg^{2+} + 2Cl^-

As you can see, from 1 molecule of MgCl2 produces 3 ions on dissociation.
So, 1 mole of MgCl2 produces 3 moles of ions.

Now, Moles of MgCl2 = Volume x Molarity

= 0.04 x 0.345   [Change volume to Litres]
= 0.0138 moles

Now, total moles of ions =  0.0138 x 3 = 0.0414
6 0
2 years ago
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