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castortr0y [4]
2 years ago
11

As the temperature of seawater increases from 15o C to 20o C, sound velocity through the seawater

Chemistry
2 answers:
Thepotemich [5.8K]2 years ago
8 0

Answer: D- increases

Explanation:

polet [3.4K]2 years ago
7 0
Answer is: d. increases.
<span>The velocity of sound in seawater changes with water pressure, depth, temperature and salinity.
</span>Velocity can be calculeted using Del Grosso's equation, the UNESCO equation (<span>International Standard algorithm)</span> or <span>Mackenzie equation.
To measure velocity navy use </span>Expendable Bathy Thermograph.

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Urea contains two nitrogen atoms. what is the source of these two nitrogen atoms?
Oksi-84 [34.3K]
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The liver<span> forms it by combining two </span>ammonia<span> molecules</span><span> with a </span>carbon dioxide<span> </span><span>molecule.</span><span />
3 0
2 years ago
At a temperature of __________ °c, 0.444 mol of co gas occupies 11.8 l at 889 torr.
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<span>ideal gas law is: PV = nRT P = pressure (torr) = 889 torr V = volume (Liters) = 11.8 L n = moles of gas = 0.444 mol R = gas constant = 62.4 (L * torr / mol * k) solve for T (in kelvin) T = PV/nR T = (889*11.8)/(.444*62.4) T = 378.6 K convert to C (subtract 273) T = 105.6 deg C</span>
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2 years ago
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Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her
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It is going to be too low because the mass mistakenly used is lower than the initial.
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If a gas has a volume of 750 mL at 25oC, what would the volume of the gas be at 55oC?
blagie [28]

Answer:

The answer to your question is     V2 = 825.5 ml

Explanation:

Data

Volume 1 = 750 ml

Temperature 1 = 25°C

Volume 2= ?

Temperature 2 = 55°C

Process

Use the Charles' law to solve this problem

                V1/T1 = V2/T2

-Solve for V2

                V2 = V1T2 / T1

-Convert temperature to °K

T1 = 25 + 273 = 298°K

T2 = 55 + 273 = 328°K

-Substitution

                V2 = (750 x 328) / 298

-Simplification

                V2 = 246000 / 298

-Result

                V2 = 825.5 ml

             

7 0
2 years ago
An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The
GuDViN [60]

Answer:Mass of Potassium chloride =1.762g

Explanation:

Mass of empty beaker = 23.100 g

Mass of beaker with Potassium chloride = 24.862g

Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride  - Mass of empty beaker = 24.862-23.100 = 1.762g

8 0
2 years ago
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