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zhuklara [117]
1 year ago
5

Ye Li drew a quadrilateral that is both a rectangle and a rhombus. Name the quadrilateral and describe it using the properties o

f sides and angles.
" describe it detaled so my teacher dosnt find out i used dis for a test"
Mathematics
1 answer:
artcher [175]1 year ago
8 0
We know that a rectangle has 2 pairs of opposite equal sides and all interior angles are right. A rhombus has 4 equal sides. If a quadrilateral is both a rectangle and rhombus, it has 4 equal sides and 4 right interior angles. That quadrilateral must be a square. 
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Tom buys a torch and a battery.
nevsk [136]

Answer:

battery costs: 0.39...............

8 0
2 years ago
While analyzing the landing procedures of airplanes, George noted one plane at an altitude of 5,000 feet descending at a rate of
Vikki [24]

Answer:

C

Step-by-step explanation:


6 0
1 year ago
Read 2 more answers
Which expressions are equivalent to (5g+3h+4)\cdot2(5g+3h+4)⋅2left parenthesis, 5, g, plus, 3, h, plus, 4, right parenthesis, do
Semenov [28]

Answer:

C None of the above

Step-by-step explanation:

The expression

(5g+3h+4)⋅2

can be expanded using distributive property as follows:

5g⋅2 + 3h⋅2 + 4⋅2  =

= 10g + 6h + 8

option A expression

(5g+3h)⋅8

can be expanded using distributive property as follows:

5g⋅8+3h⋅8 =

= 40g + 24h

which is different from 10g + 6h + 8

Option B expression

(5g+3h)⋅6

can be expanded using distributive property as follows:

5g⋅6+3h⋅6 =

= 30g + 18h

which is different from 10g + 6h + 8

6 0
1 year ago
Read 2 more answers
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) = (e^-x/1076)/
kozerog [31]

Answer:

(a) 0.06154

(b) 0.2389

(c) 0.6052

(d) 2478

Step-by-step explanation:

probability density function of the time to failure of an electronic component in a copier (in hours) is

P(x) = 1/1076e^−x/1076

λ = 1/1076

A) A component lasts more than 3000 hours before failure:

P(x>3000) = 1 − e^−3000/1076

= 0.06154

B) A component fails in the interval from 1000 to 2000 hours:

P(1000>x>2000) =1 − e^−2000/1076 − 1 +e^−1000/1076 = e^−1000/1076 − e^−2000/1076 = 0.3948 − 0.1559

= 0.2389

C) A component fails before 1000 hours:

P(x<1000) = 0.6052

D) The number of hours at which 10% of all components have failed:

e^−x/1076 = 0.1

= −x/1076

= ln(0.1)

x =(2.3026)×(1076)

x = 2478

4 0
1 year ago
If ED = 5y + 6 and DB = y + 30, find the value of y. Then find ED, DB, and EB.
Gemiola [76]

Answer:

Part 1) The value of y=6

Part 2) ED=36, DB=36 and EB=72

Step-by-step explanation:

In this problem we know that

ED=DB -----> equation A

EB=ED+DB -----> equation B

The point D is the midpoint ED

see the attached figure to better understand the problem

step 1

Find the value of y

Substitute the given values in the equation A

5y+6=y+30

solve for y

5y-y=30-6

4y=24

y=6

step 2

Find the value of ED,DB and EB

ED=5y+6

substitute the value of y

ED=5(6)+6=36

Remember that

ED=DB

therefore

DB=36

Find the value of EB

EB=ED+DB

EB=36+36=72

3 0
1 year ago
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