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2 years ago

The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?

1 answer:

8 0

1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
= 4/3 (3.142 ×12.167×10∧-24
= 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³

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A collection of coins contains 14 pennies, 16 dimes, and 7 quarters. What is the percentage of pennies in the collection?A colle

marin [14]

Answer:

=37.83783784

Explanation:

Find the total sum of all coins,

which is 37, take the number of pennies and the total of all coins put in parenthesis( 14/37) like so and than * times them by 100

you equation should look like this

(14/37)* 100= and than the answer shown above should be the one you received. I have checked this with multiple calculators, it should be accurate.

8 0

2 years ago

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Which of the following species contains manganese with the highest oxidation number?

ioda

In NaMnO₄, Mn has the highest oxidation number.

The question is incomplete, the complete question is;

Which of the following species contains manganese with the highest oxidation number?

A) Mn

B) MnF₂

C) Mn₃(PO₄)₂

D) MnCl₄

E) NaMnO₄

In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.

1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.

2) For MnF₂;

Mn has an oxidation number of +2

3) For Mn₃(PO₄)₂

Mn has an oxidation number of +2

4) For MnCl₄

Mn has an oxidation number of +4

5) For NaMnO₄

Mn has an oxidation number of +7

Hence in NaMnO₄, Mn has the highest oxidation number.

Learn more: brainly.com/question/10079361

7 0

2 years ago

Which of the following is a valid conversion factor?

VMariaS [17]

Answer:

100 cg/1g

Step-by-step explanation:

1 cg = 0.01 g Multiply by 100

100 cg = 1 g

(a) is wrong. The correct conversion factor is 1000 cm³/1 L.

(b) is wrong. The correct conversion factor is 1000 mL/1 L.

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2 years ago

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How many Cl- ions are there in 400.5 grams of AlCl3?

den301095 [7]

Answer:

The answer to your question is letter A

Explanation:

Process

1.- Calculate the molecular mass of AlCl₃

Al = 1 x 27 = 27

Cl = 3 x 35.5 = 106.5

AlCl₃ = 27 + 106.5 = 133.5

2.- Find the number of ions of Cl using proportions

133.5 grams of AlCl₃ ------------- 3 ions of Chlorine

400.5 grams of AlCl₃ ------------ x

x = (400.5 x 3) / 133.5

x = 9

6 0

2 years ago

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How many inner, outer, and valence electrons are present in an atom of each of the following elements?

Aneli [31]

Answer:

For a: The number of inner electrons, outer electrons and valence electrons are 28, 7 and 7 respectively.

For b: The number of inner electrons, outer electrons and valence electrons are 54, 1 and 1 respectively.

For c: The number of inner electrons, outer electrons and valence electrons are 23, 1 and 1 respectively.

For d: The number of inner electrons, outer electrons and valence electrons are 36, 2 and 2 respectively.

For e: The number of inner electrons, outer electrons and valence electrons are 2, 7 and 7 respectively.

Explanation:

Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons. The electrons present in the highest principle quantum number are known as valence electrons.

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Inner electrons = Total number of electrons - Valence electrons

Total number of electrons in an atom is equal to the atomic number of the element.

For the given options:

Option a: Bromine (Br)

Bromine is the 35th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^5$

Highest principle quantum number is 4

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 35 - 7 = 28

Option b: Cesium (Cs)

Cesium is the 55th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^1$

Highest principle quantum number is 6

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 55 - 1 = 54

Option c: Chromium (Cr)

Chromium is the 24th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^13d^{5}$

Highest principle quantum number is 4

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 24 - 1 = 23

Option d: Strontium (Sr)

Strontium is the 38th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2$

Highest principle quantum number is 5

Number of valence electrons = 2

Number of outer electrons = 2

Number of inner electrons = 38 - 2 = 36

Option e: Fluorine (F)

Fluorine is the 9th element of the periodic table having electronic configuration of $1s^22s^22p^5$

Highest principle quantum number is 2

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 9 - 7 = 2

4 0

2 years ago