A thin square sheet of lead measuring 2.5 inches on each side weighs 525 mg. Find the thickness (in mm) of the sheet, given the
1 answer:
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To calculate the packing factor, first calculate the area and volume of unit cell.
Area is calculated as:
Here, R is radius and is related to a as follows:
Putting the value in expression for area,
The value of a is 0.4961 nm
Since,
Thus,
Putting the value,
Now, volume can be calculated as follows:
The value of c is 1.360 nm or
Putting the value,
now, number of atom in unit cell can be calculated by using the following formula:
Here, A is atomic mass of is 151.99 g/mol.
Putting all the values,
Thus, there will be 18 units in 1 unit cell.
Since, there are 2 Cr atoms and 3 oxygen atoms thus, units of chromium and oxygen will be 2×18=36 and 3×18=54 respectively.
The atomic radii of and
is 62 pm and 140 pm respectively.
Converting them into cm:
Thus,
and,
Volume of sphere will be sum of volume of total number of cations and anions thus,
Since, volume of sphere is ,
Putting the values,
The atomic packing factor is ratio of volume of sphere and volume of crystal, thus,
Thus, atomic packing factor is 0.758.
Answer:
34.2 g is the mass of carbon dioxide gas one have in the container.
Explanation:
Moles of :-
Mass = 49.8 g
Molar mass of oxygen gas = 32 g/mol
The formula for the calculation of moles is shown below:
Thus,
Since pressure and volume are constant, we can use the Avogadro's law as:-
Given ,
V₂ is twice the volume of V₁
V₂ = 2V₁
n₁ = ?
n₂ = 1.55625 mol
Using above equation as:
n₁ = 0.778125 moles
Moles of carbon dioxide = 0.778125 moles
Molar mass of = 44.0 g/mol
Mass of = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g
<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>
Answer:
110ml
Explanation:
<em>Using the dilution equation, C1V1 = C2V2</em>
<em>Where C1 is the initial concentration of solution</em>
<em>C2 is final concentration of solution</em>
<em>V1 is intital volume of solution</em>
<em>V2 is final volume of solution.</em>
From the question , C1=6M, C2=0.5M, V1=10ml, V2=?
volume of water added = final volume -initial volume
= 120-10
=110ml