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Alja [10]
2 years ago
8

The owner of a bakery wants to know whether customers have any preference among 5 different flavors of muffin. A sample of 200 c

ustomers provided the data below. Use a = 0.01. The table below shows how many people were tested at each location and their stated preferences Flavor Orange Blueberry Chocolate Vanilla Vanilla and Raisins # of customers 30 52 38 36 44 Calculate the chi-square test statistic X 2. Test the claim that the probabilities show no preference.
Mathematics
1 answer:
Troyanec [42]2 years ago
8 0
So,, there are 5 different flavors. A total of 180 people were asked. Hence, the hypothesis that there is no significant difference is that every flavor gets 180/5=36 flavors. x^2=\sum{\frac{(x_i)^2}{m_i}}-n. In this case, mi is the proportion of the hypothesis, thus 36, n=180 and xi is the number of actual observations. Substituting the known quantities, we get that x^2=9. The degree of association is given by \sqrt{X^2}/ \sqrt{N(n-1)}. This yields around 0.10, much higher than our limit.
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Given a positive integer n, assign true to is_prime if n has no factors other than 1 and itself. (remember, m is a factor of n i
yawa3891 [41]
This is the following condition in order to get the specific output for this specific problem: if is_a_prime(n):<span>    is_prime = True</span> <span><span>Now all you have to do is write is_a_prime().

For the hard code for this problem:

</span>if n == 2:<span>
is_prime = True
elif n % 2 == 0:
is_prime = False
else:
is_prime = True 
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if n % m == 0: 
is_prime = False 
<span>break.</span></span></span> 
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6 0
2 years ago
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Find the point estimate of the proportion of people who wear hearing aids if, in a random sample of 493 people, 40 people had he
Anna71 [15]
Point estimate proportion is the average of lower and upper interval limit.

Point estimate proportion )p) = x/n
Where x = observations, n=sample size

Substituting;

p= 40/493 = 0.0811
8 0
2 years ago
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Tyrone paid $234.33 for a new watch, after tax, and the tax rate is 7%. What was the original price of the watch?
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The cost of the watch originally cost $1,640.31
6 0
2 years ago
Budget planners in two towns, Alphaville and Betaville, developed models to determine the budget surplus (in dollars) for a year
kramer

Answer:

(a)-3x^2+150x-10000

(b)-\$16,863,760,000

Step-by-step explanation:

Alphaville's Budget Surplus Model is -2x^2+ 500x

Betaville's Budget Surplus Model is x^2- 100x + 10000.

We want to determine the expression that shows how much greater Alphaville’s annual budget surplus is than Betaville’s for a particular amount of tax revenue.

  • To do this, we subtract Betaville's Model from Alphaville's model.

-2x^2+ 500x-(x^2- 100x + 10000)\\

Opening the brackets

-2x^2+ 500x-x^2+100x - 10000\\

Collect like terms and simplify

-2x^2-x^2+100x + 500x- 10000\\=-3x^2+150x-10000

The expression that shows how much greater Alphaville's Budget is:

-3x^2+150x-10000

(b) If the tax revenue that year in each town is $75,000

We want to evaluate the expression derived above when the tax revenue that year in each town is $75,000 i.e.at x=75000

-3x^2+150x-10000\\=-3(75000)^2+150(75000)-10000\\=-\$16,863,760,000

3 0
2 years ago
Consider a data set with at least three data values. Suppose the highest value is increased by 10 and the lowest is decreased by
bulgar [2K]

Answer:

a. Mean doesn't change.

b. Median doesn't change.

c. Mode can change.

Step-by-step explanation:

Let us assume the data set with 10 observations

{2,6,4,3,2,6,4,9,4,7}.

Arranging data set in ascending order

{2,2,3,4,4,4,6,6,7,9}

mean=2+2+3+4+4+4+6+6+7+9/10=4.7

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Mode

The most repeated value is 4. So, mode is 4 for assumed data.

Increasing highest value by 10 and decreasing lowest value by 10

{-8,2,3,4,4,4,6,6,7,19}

a.

mean=-8+2+3+4+4+4+6+6+7+19/10=4.7

Mean doesn't change

b.

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Median doesn't change

c.

Most occurring value is still 4. But mode can change if the value the highest value becomes most concurring value.

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2 years ago
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