A drag racer completes a race in 14.3 s. If the drag racer has an average speed of 251 km/h, how long is the racetrack?

Physics

2 answers:

RSB [31]2 years ago

7 0

Answer:

$996.99 \ m/s$

Explanation:

Time taken to complete the race, $t=14.3 \ s$ .

Average speed, $v=251 \ km/h$ .

First we will convert v in $m/s$ .

Therefore, $v=\dfrac{251\times 1000}{3600}\ m/s =69.72 \ m/s$ .

Now, length of racetrack is given by , $D=v\times t$ .

$D=69.72\times 14.3 \ m=996.99 \ m$ .

Hence, this is the required solution.

ivanzaharov [21]2 years ago

3 0

Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)²)/r
= ((2³.14*50/14.3)²)/50
<span>= 9.64 m/s</span>²

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