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Paha777 [63]
2 years ago
4

An energy value of 3.313 × 10^{-19} joules is needed to break a chemical bond. What is the wavelength of energy needed to break

the bond? (The speed of light = 3.00 × 10¹⁰ cm/sec; Planck’s constant = 6.626 × 10^{–34} J ⋅sec).
A. 5.00 × 10¹⁸ cm
B. 1.00 × 10¹⁵ cm
C. 2.00 × 10⁵ cm
D. 6.00 × 10^{–5}cm
E. 1.20 × 10^{–8} cm
Can someone explain me how to make this one step by step?
Chemistry
1 answer:
algol [13]2 years ago
6 0
You need two formulas. You need E = hf and v = wavelength x frequency. Plug in the values for the first formula. f = 3.3 x 10^-19/6.63 x 10^-34 and you get f = 0.5 x 10^15. Now plug in this number to the second equation. Wavelength = 3.00 x 10^10 cm/sex/0.5 x 10^15 and you get D) 6.00 x 10^-5 cm.
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2 years ago
An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i
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The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
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The unit is g/cm³

It is given:
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V = 205 mL = 205 cm³
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Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
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2 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
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Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

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7 0
2 years ago
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Answer:

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Explanation:

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Answer:

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An octet is always formed via ionic bonding

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