3x - 2y + 2 = 0 → -2y + 2 = -3x → -2y = -3x - 2 → y = 
x + 1
x - y + 3 = 0 → -y + 3 = -x → -y = -x - 3 → y = x + 3
These two equations have the same slope but different y-intercepts so they are parallel lines. (aka inconsistent).
Answer: Inconsistent, (0, 1), (0, 3)
Answer:
He must get 33 hits in his next 46 times at bat to finish the year with a .400 batting average
Step-by-step explanation:
The player has already batted 134 times and will still bat 46 times. So in the end of the year, he is going to have 134 + 46 = 180 at bats.
How many hits does he need to have to hit .400?
This is 40% of 180, which is 0.4*180 = 72.
He has already 39 hits, so in his next 46 at bats, he will need 72 - 39 = 33 hits.
Answer:
Step-by-step explanation:
Given a sample M(t)
M(t) = 120 • ( 81 / 625)^t
When is the fraction of the mass decay to 3/5 of it's mass
Generally
M(t) = Mo•(k^t)
The original mass is 120
Mo = 120
So, we want to find time when it decay to 3/5 of it's original mas
M = 3/5 × 120
M = 72
Then,
M(t) = 120 • ( 81 / 625)^t
72 = 120 • ( 81 / 625)^t
72 / 120 = ( 81 / 625)^t
0.6 = ( 81 / 625)^t
Take natural logarithmic of both sides
In(0.6) = In(81/625)^t
In(0.6) = t•In(81/625)
t = In(0.6) / In(81/625)
t = In(0.6) / In(0.1296)
t = 0.25 monthly
t = ¼ monthly
= 6.37 * 10^4 = 637 * 10^2 = 63700
In short, Your Answer would be Option A
Hope this helps!
Answer:
Step-by-step explanation:
Let the length and breadth be 5x and 4x respectively.
Area of rectangular field = 18000 m²
<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x</u>
Area of rectangle = 
Plug the values
⇒
Calculate the product
⇒
Swap the sides of the equation
⇒
Divide both sides of the equation by 20
⇒
Calculate
⇒
Squaring on both sides
⇒
<u>Replacing the value of x in order to find the value of length and breadth</u>
Length = 
Breadth = 
<u>Finding </u><u>the </u><u>perimeter</u><u> </u><u>of </u><u>the </u><u>rectangular</u><u> </u><u>field</u>
Perimeter of rectangle = 
plug the values
⇒
Distribute 2 through the parentheses
⇒
Add the numbers
⇒
Hope I helped !
Best regards!!
