Answer: The rate of disappearance of 
is 
Explanation:
The given chemical reaction is:
The rate of the reaction for disappearance of is given as:
![\text{Rate of disappearance of }NO_2=-\frac{\Delta [NO_2]}{\Delta t}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DNO_2%3D-%5Cfrac%7B%5CDelta%20%5BNO_2%5D%7D%7B%5CDelta%20t%7D)
Or,
where,
= final concentration of = 0.00650 M
= initial concentration of = 0.0100 M
= final time = 100 minutes
= initial time = 0 minutes
Putting values in above equation, we get:
Hence, the rate of disappearance of is
Answer:
The following subsections explain the explanation according to the particular circumstance.
Explanation:
- The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.
- The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.
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Answer:
43.96
Explanation:
Graham's law was applied and the rates of effusion of nitrogen and the unknown gas were compared as shown in the image. The unknown gas is heavier than hydrigen hence it effuses slower than hydrogen as anticipated by Graham's law.
