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blondinia [14]
2 years ago
10

Determine the volume of hexane that contains 5.33 × 1022 molecules of hexane. The density of hexane is 0.6548 g/ml and its molar

mass is 86.17 g/mol.
Chemistry
1 answer:
algol [13]2 years ago
5 0

we are asked to find the volume of hexane. Density is mass per given volume.

1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up an element or molecules making up a compound.

the number of molecules in hexane has been given therefore we can find the number of moles of hexane

6.022 x 10²³ molecules make up - 1 mol

therefore 5.33 x 10²² molecules make - 1 / (6.022 x 10²³) x 5.33 x 10²²

                                                               = 0.0885 mol

since we know the molar mass and number of moles, mass of hexane can be calculated

mass of hexane = 86.17 g/mol x 0.0885 mol = 7.63 g

density has been given, therefore we can find the volume

volume = mass / density

volume = 7.63 g / 0.6548 g/ml = 11.7 ml

volume of hexane is 11.7 ml

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<h3>Answer:</h3>

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<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

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where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

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A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solu
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Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = 6.05\times 10^3 kg=6.05\times 10^6 g

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Percentage mass of sulfuric acid = 95.0%

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According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

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