Question

Complete the tasks to subtract the polynomials vertically. (1.3t3 + 0.4t2 – 24t) – (0.6t2 + 8 – 18t) What is the additive inverse of the polynomial being subtracted? –0.6t2 + (–8) + (–18t) –0.6t2 + (–8) + 18t –0.6t2 + 8 – 18t 0.6t2 + (–8) + 18t

Answer 1

Answer:

$-0.6t^2-8+18t$

Step-by-step explanation:

We know that the additive inverse are two equal numbers or expressions but with different signs.

Now, the given polynomials are:

$(1.3t^3+0.4t^2-24t)-(0.6t^2+8-18t)$

The additive inverse is:

$-0.6t^2-8+18t$ which is the same expression as $(0.6t^2+8-18t)$ but with different signs.

Thus, the additive inverse of the polynomial being subtracted is:

$-0.6t^2-8+18t$

Answer 2

The correct answer is B. –0.6t2 + (–8) + 18t