On a cold day near the ocean it was found that 8g of an unknown gas occupies a volume that is a little less than 6 l. based on t
2 answers:
You might be interested in
1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu
2) we need to convert the grams of CuSO₄ to moles using the molar mass.
molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol
3) convert moles of CuSO₄ to moles of Cu
4) convert moles of Cu to grams using it's molar mass.
molar mass Cu= 63.5 g/mol
I did it step-by-step as the explanation but you can do all of this in one step.
2) we need to convert the grams of CuSO₄ to moles using the molar mass.
molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol
3) convert moles of CuSO₄ to moles of Cu
4) convert moles of Cu to grams using it's molar mass.
molar mass Cu= 63.5 g/mol
I did it step-by-step as the explanation but you can do all of this in one step.
Answer:
Explanation:
Hello!
In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:
Now the entropy at the final state given the new 40-% quality:
Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:
Then, we can write the entropy balance:
Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:
Which is such minimum entropy change of the heat-supplying source.
Best regards!