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Step2247 [10]
2 years ago
10

Acetone can be easily converted to isopropyl alcohol by addition of hydrogen to the carbon–oxygen double bond. calculate the ent

halpy of reaction using the bond energies given. bond: c=o h–h c–h o–h c–c c–o bond energy (kj/mol): 745 432 413 467 347 358 multiple choice –61 kj +61 kj –366 kj –484 kj +366 kj
Chemistry
1 answer:
Step2247 [10]2 years ago
7 0

Answer:

-484kJ

Explanation:

Carry out bond energy calculation

[6(C-H) + (C=O) +2(C-C)] - [(O-H) +7(C-H)+ (C-O) +2(C-C)]

Substitute the bond energy values = -484kJ

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Rubbing alcohol contains 615g of isopropanol (C3H7OH) per liter (aqueous solution). Calculate the molality of this solution. Giv
faltersainse [42]

Answer:

Solution of isopropanol is 10.25 molal

Explanation:

615 g of isopropanol (C3H7OH) per liter

We gave the information that 615 g of solute (isopropanol) are contained in 1L of water. We need to find out the mass of solvent, so we use density.

Density of water 1g/mL → Density = Mass of water / 1000 mL of water

Notice we converted the L to mL

Mass of water = 1000 g (which is the same to say 1kg)

Molality are the moles of solute in 1kg of solvent, so let's convert the moles of isopropanol  → 615 g . 1mol / 60g = 10.25 moles

Molality (mol/kg) = 10.25 moles / 1kg = 10.25 m

4 0
2 years ago
For the reaction PCl5(g) <--> PCl3(g) Cl2(g) at equilibrium, which statement correctly describes the effects of increasing
xenn [34]

The given question is incomplete. The complete question is :

For the reaction PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g) at equilibrium, which statement correctly describes the effects of increasing pressure and adding PCl_5, respectively

a) Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

b) Increasing pressure causes shift to products ,adding PCl_5 causes shift to reactants.

c) Increasing pressure causes shift to products, adding PCl_5 causes shift to products.

d) Increasing pressure causes shift to reactants,adding PCl_5 causes shift to reactants

Answer: Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

a)  If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.

b) If PCl_5 is added, the equilibrium will shift in the direction where PCl_5 is decreasing. So, the equilibrium will shift in the right direction. i.e. towards products.

8 0
2 years ago
The table below gives some characteristics of element Y. Characteristics of element Y Values Mass number 11 Number of neutrons i
Elden [556K]
I believe the answer is Na because it should be sodium which is Na.
6 0
2 years ago
Read 2 more answers
A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the s
Yuri [45]

Answer:

The answer is

\huge 4\%

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

p(\%) =  \frac{0.25}{6.25}  \times 100

We have the final answer as

<h3>4 %</h3>

Hope this helps you

3 0
2 years ago
During a titration the following data were collected. A 10. mL portion of an unknown monoprotic acid solution was titrated with
Liula [17]

Answer:

8.0 moles

Explanation:

Since the acid is monoprotic, 1 mole of the acid will be required to stochiometrically react with 1 mole of NaOH.

Using the formula: \frac{concentration of acid X volume of acid}{concentration of base X volume of base} = \frac{mole of acid}{mole of base}

Concentration of acid = ?

Volume of acid = 10 mL

Concentration of base = 1.0 M

Volume of base = 40 mL

mole of acid = 1

mole of base = 1

Substitute into the equation:

\frac{concentration of acid X 10}{1.0 X 40} = \frac{1}{1}

Concentration of acid = 40/10 = 4.0 M

To determine the number of moles of acid present in 2.0 liters of the unknown solution:

Number of moles = Molarity x volume

molarity = 4.0 M

Volume = 2.0 Liters

Hence,

Number of moles = 4.0 x 2.0 = 8 moles

8 0
2 years ago
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