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2 years ago

A flask contains 0.230 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

2 answers:

7 0

The amount of bromine present in the flask = 0.230 moles
Avagadro's number states the number of units present in a single mole.
Avagadro's number is 6.022 x 10²³ units, these could be atoms in the case of elements or molecules in compounds.
the number of bromine molecules in 1 mol = 6.022 x 10²³ molecules of Br bromine molecules in 0.230 mol = 6.022 x 10²³ molecules/mol x 230 mol

number of bromine molecules in the flask = 1.385 x 10²⁶ Br₂ molecules

Lostsunrise [7]2 years ago

5 0

Answer:

There are $1.38506\times 10^{23}$ of bromine molecules present in the flask.

Explanation:

Moles of liquid bromine in the flask = 0.230 mol

As we know that 1 mole is equal to the Avogadro number.

$1 mol=6.022\times 10^{23}$ atoms/ molecules

So, number of bromine molecules in 0.230 moles of liquid bromine is:

$=0.230\times 6.022\times 10^{23}=1.38506\times 10^{23} molecules$

There are $1.38506\times 10^{23}$ of bromine molecules present in the flask.

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I hope it helps!

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2 years ago