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Juli2301 [7.4K]
2 years ago
13

A slice of pizza contains 29 g of carbohydrate, 13 g of protein and an unknown amount of fat. if the pizza contains 280 kcal, ho

w many grams of fat are present? report the answer to 2 significant figures.
Chemistry
2 answers:
damaskus [11]2 years ago
4 0

Answer:

12 g

Explanation:

Shalnov [3]2 years ago
3 0
When different macronutrients (e.g., carbohydrates) are metabolized, they yield different amounts of energy, commonly measured in kilocalories.

They are given by the following conversion factors:

carbohydrates = 4 kcal/g
protein = 4 kcal/g
fat = 9 kcal/g

If the slice of pizza contains 29 g carbohydrates, that means there are 4 kcal/g × 29 g = 116 kcal from carbohydrates. It contains 13 g protein, so there are 4 kcal/g <span>× 13 g = 52 kcal from protein.

The total number of kilocalories is 280, of which we have accounted for 168 (116+52). 280–168=112 kcal.

So, there are 112 kcal from fat. Using our conversion factor, 112 kcal </span><span>× 1 g/9 kcal = 12 g fat.</span>
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Which term names the metamorphic change to a rock that results mainly from the heat energy of nearby magma? A. local metamorphis
marshall27 [118]
The answer to this question would be: <span>thermal metamorphism
</span>
Metamorphism is a change in the mineral texture without causing the rock to become liquid/magma. In this case, the metamorphic change to the rock is caused by the heat energy or thermal energy of the magma. This kind of mechanism is also called contact mechanism as the thermal energy is transferred by contact so this question option is a bit ambiguous.
8 0
2 years ago
Read 2 more answers
A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
REY [17]

Answer:

Sn_2O

Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO

In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1

Therefore, the empirical formula is:

Sn_2O

Best regards.

8 0
2 years ago
In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan
Advocard [28]

Answer:

Manganese, Fifth transition element

[X] 3d⁶ 4s¹

Iron, Sixth transition element

[X] 3d⁶ 4s²

Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

And according to Aufbau's principles that electrons fill the lower energy orbitals before they fill higher energy orbitals and Hund's Rule that states that electrons are fed singly to all the orbitals of a subshell before pairing occurs.

The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

So, in the new universe L, where there are six d orbitals, for manganese, the fifth transition metal, because half filled orbitals are more stable than partially filled orbitals (that woukd have been rhe case if we leave 5 electrons on the 3d orbital), the 4s orbital is filled to half of its capacity and the one electron removed from the 4s is used to fill the six 3d orbital to half of its capacity too.

For the sixth transition element, the new extra electron just fills the lower energy 4s orbital, leaving the six 3d orbitals all half-filled.

Hence, they both have ground state configurations of

- Manganese, Fifth transition element

[X] 3d⁶ 4s¹

- Iron, Sixth transition element

[X] 3d⁶ 4s²

Hope this Helps!!!

7 0
2 years ago
A person loses 2.70 lbs in two weeks how many grams did he lose?
Evgesh-ka [11]
He person lost 1224.7 grams.
6 0
3 years ago
Read 2 more answers
Why is the wavelength of 633 nm used to analyze the standard solutions and drink samples?
RUDIKE [14]

Answer:

Corresponding with orange light, is the wavelength that blue solutions absorb the most.

Explanation:

If light is diffused through a solution of a given color, emerges of light from another wavelength is consumed and fades away. However, the wavelength of light relating to the color of such a solution is transferred. The color of the light is consumed is usually the contrasting one being transferred. As seen in a color wheel where, blue complement orange, red complement green, and yellow complement violet.

Thus, for a blue substance in solution, its complementary color is said to be orange, Given that the wavelength of orange color varies from 600 - 640 nm where it's maximum absorbance is approximately 633 nm. This wavelength is what is employed when analyzing the standard solutions and drink samples.

6 0
1 year ago
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