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Juli2301 [7.4K]
2 years ago
13

A slice of pizza contains 29 g of carbohydrate, 13 g of protein and an unknown amount of fat. if the pizza contains 280 kcal, ho

w many grams of fat are present? report the answer to 2 significant figures.
Chemistry
2 answers:
damaskus [11]2 years ago
4 0

Answer:

12 g

Explanation:

Shalnov [3]2 years ago
3 0
When different macronutrients (e.g., carbohydrates) are metabolized, they yield different amounts of energy, commonly measured in kilocalories.

They are given by the following conversion factors:

carbohydrates = 4 kcal/g
protein = 4 kcal/g
fat = 9 kcal/g

If the slice of pizza contains 29 g carbohydrates, that means there are 4 kcal/g × 29 g = 116 kcal from carbohydrates. It contains 13 g protein, so there are 4 kcal/g <span>× 13 g = 52 kcal from protein.

The total number of kilocalories is 280, of which we have accounted for 168 (116+52). 280–168=112 kcal.

So, there are 112 kcal from fat. Using our conversion factor, 112 kcal </span><span>× 1 g/9 kcal = 12 g fat.</span>
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Silver chloride is formed by mixing silver nitrate and barium chloride solutions. What volume of 1.50 M barium chloride solution
konstantin123 [22]

Answer:

1.22 mL

Explanation:

Let's consider the following balanced reaction.

2 AgNO₃ + BaCl₂ ⇄ Ba(NO₃)₂ + 2 AgCl

The molar mass of silver chloride is 143.32 g/mol. The moles corresponding to 0.525 g are:

0.525 g × (1 mol/143.32 g) = 3.66 × 10⁻³ mol

The molar ratio of AgCl to BaCl₂ is 2:1. The moles  of BaCl₂ are 1/2 × 3.66 × 10⁻³ mol = 1.83 × 10⁻³ mol.

The volume of 1.50 M barium chloride containing 1.83 × 10⁻³ moles is:

1.83 × 10⁻³ mol × (1 L/1.50 mol) = 1.22 × 10⁻³ L = 1.22 mL

8 0
1 year ago
A student uses visible spectrophotometry to determine the concentration of CoCl2(aq) in a sample solution. First the student pre
k0ka [10]

Answer:

4\times 10^{-9} J is the approximate energy of one photon of this light.

Explanation:

Energy of the photon can be calculated by

E=h\nu=\frac{h\times c}{\lambda}  (Planck's equation)

where,

E = energy of photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light =

\nu = frequency of the light

we have , \lambda =510 nm=510\times 10^{-9}m

Now put all the given values in the above formula, we get the energy of the photons.

E=\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{510\times 10^{-9}m}

E=3.9\times 10^{-19}J\approx 4\times 10^{-9} J

4\times 10^{-9} J is the approximate energy of one photon of this light.

5 0
2 years ago
One of the commercial uses of sulfuric acid is the production of calcium sulfate and phosphoric acid. If 19.9 g of Ca₃(PO₄)₂ rea
Natasha_Volkova [10]

57.5 % is the percent yield if 10.9 g of H₃PO₄ is formed.

Explanation:

Balanced equation for the reaction:

Ca₃(PO₄)₂ (s) + 2H₂SO₄ (aq) → H₃PO₄ (aq) + 2CaSO₄ (aq)

data given:

mass of Ca₃(PO₄)₂ = 19.9 grams

mass of  H₂SO₄, = 54.3 grams

mass of H₃PO₄ produced = 10.9 grams (actual yield)

percent yield=?

atomic mass of Ca₃(PO₄)₂  = 310.17 grams/mole

atomic mass of H₂SO₄ = 98.07 grams/mole

number of moles is calculated as:

number of moles  = \frac{mass}{atomic mass of one mole}

putting the values in the above equation:

for Ca₃(PO₄)₂  = \frac{19.9}{310.17}

                        = 0.064 moles

moles of H₂SO₄ = \frac{54.3}{98.07}

                            = 0.55 moles

from the reaction, it can be found that the limiting reagent is Ca₃(PO₄)₂

1 mole of Ca₃(PO₄)₂ reacts to form 1 mole of phosphoric acid

0.064 moles of  Ca₃(PO₄)₂ will produce x moles of phosphoric acid

0.064 moles of phosphoric acid produced

mass = number of moles x atomic mass of  H3PO4

             =0.064 x 97.994

           = 6.27 grams (theoretical yield)

FORMULA FOR PERCENT YIELD:

percent yield = \frac{actual yield}{theoretical yield} x 100

                      = \frac{6.27}{10.9} x 100

                       = 57.5 %

7 0
2 years ago
A heat energy of 645 J is applied to a sample of glass with a mass of 28.4 g. Its temperature increases from –11.6 ∞C to 15.5 ∞C
Anika [276]
The heat that is required to raise the temperature of an object is calculated through the equation,
                        heat = mass x specific heat x (T2 - T1)
Specific heat is therefore calculated through the equation below,
                                specific heat = heat / (mass x (T2 - T1))
Substituting,
                                specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The value of specific heat from above equation is 0.838 J/g°C. 
5 0
2 years ago
Phosphofructokinase catalyzes the phosphorylation of fructose 6‑phosphate to fructose 1,6‑bisphosphate in glycolysis. Fructose 1
umka2103 [35]

Answer:

d. increases PFK activity, decreases FBPase activity

Explanation:

Fructose-2,6-bisphophate is formed by the phosphorylation of fructose-6-phosphate catalyzed by phosphofructokinase-2, PFK-2.

Fructose-2,6-bisphophate functions as an allosteric effector of the enzymes phosphofructokinase-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase.

Fructose-2,6-bisphophate has opposite effects on the enzymes, PFK-1 and FBPase. When it binds to the allosteric site of the enzyme, PFK-1, it increases the enzymes's activity by increasing its affinity for its substrate fructose-6-phosphate and reduces its affinity for its allosteric inhibitors ATP and citrate. However, when it binds to FBPase, it reduces its activity by reducing its affinity for glucose, its substrate

3 0
1 year ago
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