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Svet_ta [14]
2 years ago
9

Solid magnesium carbonate (mgco3) and solid sodium nitrate were mixed, placed in water, and stirred. what is observed? 1. mgco3

and nano3 will not dissolve. 2. mgco3 and nano3 will dissolve. 3. mgco3 will remain undissolved and nano3 will dissolve. 4. nano3 will remain undissolved and mgco3 will dissolve.
Chemistry
2 answers:
Dmitriy789 [7]2 years ago
6 0

Answer: Option (3) is the correct answer.

Explanation:

When lattice energy of a compound is more than its hydration energy then the compound is insoluble in water.

Moreover, magnesium carbonate is a precipitate formed by chemical combination of aqueous solutions of magnesium chloride and sodium bicarbonate.

On the other hand, hydration energy of sodium nitrate is more than its lattice energy. Therefore, sodium nitrate is soluble in water and it will readily dissolve.

thus, we can conclude that MgCO_{3} will remain undissolved and NaNO_{3} will dissolve.

Komok [63]2 years ago
3 0
MgCO3 will remain undissolved and
NaNO3 will dissolve
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Luden [163]

Answer:

50 mm

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1 L

Explanation:

Centimeter to  millimeter:

1 cm is equal to 10 mm.

5cm× 10 mm/1 cm

50 mm

Inches to feet conversion:

1 foot is equal to 12 inches.

48 inch ×  1 feet /12 inch

4 feet

Yard to Feet conversion:

1 yard is equal to 3 feet.

12 yd × 3 ft / 1 yd

36 ft

Meter to centimeter:

One meter is equal to 100 cm.

2.5 m × 100 cm / 1m

250 cm

Milliliter to Liter:

One L is equal to 1000 mL.

1000 mL = 1 L

4 0
2 years ago
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If a runner completes a 10 kilometer race in 32.50 minutes, what is the 10.0 km pace in miles per hour? (1.609 km = 1 mile appro
Elina [12.6K]
If a runner completes a 10 km race in 32.5 minutes, his pace or speed can be calculated by the equation:

velocity = distance/time = 10km/32.5 mins = 0.3125 km/min

Convert this value to miles per hour using the conversion factors for minutes to hours and kilometers to miles as requested by the problem. This gives an answer of 11.47 miles per hour.

0.3125 km/min x 60 mins./ 1 hour x 1 mile / 1.609 km = 11.47 miles/hour
3 0
2 years ago
The table shows the amount of radioactive element remaining in a sample over a period of time.
MrRissso [65]

Answer:

8,000 years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

Part 1: What is the half-life of the element? Explain how you determined this.

  • The half-life of the element is 1,600 years.

Half-life time is the time needed for the reactants to be in its half concentration.

The sample stats with 56.0 g and reaches its half concentration (28.0 g) after 1,600 years.

<em>So, the half-life of the sample is 1,600 years.</em>

<em></em>

Part 2: How long would it take 312 g of the sample to decay to 9.75 grams? Show your work or explain your answer.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1,600 years) = 4.33 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 4.33 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 312.0 g).

[A] is the remaining concentration of the sample ([A] = 9.75 g).

<em>∴ t = (1/k) ln([A₀]/[A])</em> = (1/4.33 x 10⁻⁴ year⁻¹) ln(312.0 g/9.75 g) = <em>8,000 years</em>.

6 0
2 years ago
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ohaa [14]

Answer:

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T½ = In2 / λ

But λ = ?

In(N/No) = -λt

In(10/20) = -(λ * 16)

In(0.5) = -16λ

-0.693 = -16λ

λ = 0.693 / 16

λ = 0.0433

Note : λ is known as the disintegration constant

T½ = In2 / λ

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T½ = 16hours

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Explanation:

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Thus, we can conclude that there is one sulfur atom in the products.

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2 years ago
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