According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams
2 answers:
A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.
Unsaturated solution has solute in lower proportions than required to form a saturated solution.
Supersaturated solution has solute in amounts greater than a saturated solution.
We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.
The solubility of KI at 10 is 136 g/ 100 mL water
The solubility of at
is 21 g/100 mL water.
The solubility of at
is 80 g/100 mL water.
The solubility of NaCl at is 38 g/ 100 mL water.
So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at .So, if we have 80g KI/ 100mL water it would be an unsaturated solution.
You might be interested in
The model would look something like the image below.
There would be a <em>central nucleus</em> containing <em>20 protons</em> and <em>20 neutrons</em>.
Surrounding the nucleus would be four concentric rings (energy levels) containing <em>20 electron</em>s.
Going out from the nucleus, the number of electrons in each ring would
be <em>2, 8, 8, 2</em>.
Answer:
1.82 g is the maximum mass of CuS.
Explanation:
Considering:
Or,
Given :
<u>For :
</u>
Molarity = 0.500 M
Volume = 38.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 38.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.019 moles
</u>
<u>For :
</u>
Molarity = 0.600 M
Volume = 42.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 42.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.0252 moles
</u>
According to the given reaction:
1 mole of reacts with 1 mole of
So,
0.019 mole of reacts with 0.019 mole of
Moles of = 0.019 mole
Available moles of = 0.0252 mole
<u>Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.</u>
The formation of the product is governed by the limiting reagent. So,
1 mole of gives 1 mole of
0.019 mole of gives 0.019 mole of
Moles of formed = 0.019 moles
Molar mass of = 95.611 g/mol
Mass of = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g
<u>1.82 g is the maximum mass of CuS.</u>